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3 years ago

Please helppppppp!! Asap!!

Mathematics

1 answer:

BabaBlast [244]3 years ago

7 0

Answer:

$\frac{2}{5}$

Step-by-step explanation:

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Geometry: solve for x

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The answer is x = 45

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4 years ago

1) Which expression is NOT equivalent to the given expression?42y - 8 -

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It has to be d because the rest equal to 24y-&

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(1 point) Use the graph below to find exact values of the indicated derivatives, or state that they do not exist. If a derivativ

svetlana [45]

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

$\mathbf{h(x) = f(g(x))}$

Start by calculating the equations of f(x) and g(x)

Graph f(x)

The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

$\mathbf{f(x) = \frac{3}{2}x,\ 0 \le x \le 2}$

$\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}$

Graph g(x)

The slope of g(x) is: -1/2

So, the equation is:

$\mathbf{g(x) = -\frac 12x}$

For x = 1 and x = 2, we have:

So, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}$

Open brackets

$\mathbf{h(x) = -\frac{3}{4}x}$

Differentiate

$\mathbf{h'(x) = -\frac{3}{4}}$

So:

$\mathbf{h'(1) = -\frac{3}{4}}$

$\mathbf{h'(2) = -\frac{3}{4}}$

For x = 3, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}$

$\mathbf{h(x) = \frac{3}{4}x}$

Differentiate

$\mathbf{h'(x) = \frac{3}{4}}$

Substitute 3 for x

$\mathbf{h'(3) = \frac{3}{4}}$

Hence, the values of the derivatives are:

$\mathbf{h'(1) = -\frac{3}{4}}$ , $\mathbf{h'(2) = -\frac{3}{4}}$ and $\mathbf{h'(3) = \frac{3}{4}}$

Read more about graphed functions at:

brainly.com/question/11804653

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3 years ago

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A system of equations and its solution are given below.

ratelena [41]

Answer:

Step-by-step explanation:

The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.

To do that, we need to multiply the first equation by 5.

5 (-x − 2y = 7)

-5x − 10y = 35

Add to the second equation. Notice the x terms cancel out.

(-5x − 10y) + (5x − 6y) = 35 + (-3)

-16y = 32

Combining this new equation with the first equation from system A will get us system B.

-x − 2y = 7

-16y = 32

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3 years ago

Estimate the quotient of 1246 divided by 4

VladimirAG [237]

Answer:

623/2

Step-by-step explanation:

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