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tatiyna
3 years ago
8

Which additional information could be used to prove that the triangles are congruent using AAS or ASA? Check all that apply.

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

Consider the given triangles.

Given: \angle C \cong \angle Q

ASA congruence criterion states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

AAS congruence criterion states that if two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider the first part:

1. In triangles ABC and QPT

If we take \angle B \cong \angle P , BC \cong PQ along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

2. If we take \angle A \cong \angle T and AC= TQ=3.2 along with the given condition.

Then the triangles are congruent by ASA congruence criterion.

3. As,\angle C \cong \angle Q, \angle A \cong \angle T and \angle B \cong \angle P, so the triangles can not be congruent.

4. If we take \angle A \cong \angle T and BC \cong PQ along with the given condition.

Then the triangles are congruent by AAS congruence criterion.

5. If we take AC=TQ=3.2 and CB=QP=3.2 along with the given condition, then the triangles are congruent but by SAS congruence criteria neither by ASA nor AAS congruence criterion.

Ksju [112]3 years ago
7 0

Answer: it’s A,B, and D

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Answer:

Domain: -2\leq x\leq 2

Range: 0\leq y\leq 4

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6 0
3 years ago
Northside Middle School spent $1187.50 on<br> 95 math books. How much did each book<br> cost?
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6 0
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3 years ago
Given the following table, determine the missing value.
sergeinik [125]
We know that
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so

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for decay factor=0.64
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Jerry has taken a random sample of students and determined the number of electives that each student in his sample took last yea
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The sample proportion of the the students that took fewer than the mean number of electives is given by the number of people who took less that the mean number of electives (i.e. 7.63) divided by the total number of students in the sample (i.e. 19). The total number of people who took less than 7.63 electives is 10. Therefore, the required sample proportion is 10 / 19.

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