How much is 3.6 divided by 0.09

Evaluate the expression<br><br> x^2 (y - 2)<br> —————, if x=3, and y= -1<br> 3y

vitfil [10]

Answer:

$\huge\boxed{\sf 9}$

Step-by-step explanation:

$\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

4 0

2 years ago

Read 2 more answers

An oral surgeon is tracking how many patients were referred to him by various local dentists. In the past year, 5 dentists made

Hoochie [10]

The mode is 6 because it repeats

6 0

2 years ago

Read 2 more answers

Please help on these two

jeyben [28]

Answer:

For your first problem you want to see what all the sides would equal

You would have to combine them all into one big equation

5x-7+3x+1+4x=30 (now you want to combine like terms)

12x-7+1=30 (combined the x's together)

12x-6=30 (added -7 and 1)

12x=36 (added 6 to each side)

x=3 (divided 12 to each side)

Now you wanna plug 4 in for x for each side to find out the largest to smallest

AB=5(3)-7= 8

BC=3(3)+1= 10

AC=4(3)= 12

So in order from smallest to largest would be angle C, B, A because

Angle C is the smallest angle because the sides AC and BC are the longest so they form the smallest angle

Then it would be angle A being the largest because the smallest sides in length AB and BC make up the biggest angle

The next problem would be that in order for it to have to be a triangle the two smallest sides needs to add up higher than the third side so

11, 11, 24, 11+11=22, which is less than 24 so not this one

18,12,9, 9+12=21 which is greater that 18 so this one would be a triangle

9,10,19, 9+10=19 which 19 isn't greater than 19 so this one is not a triangle

4,7,23, 4+7=11 which is less than 23, so this one is also not a triangle

So your answer would be 18cm,12cm,9cm

8 0

3 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

or

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: