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Llana [10]
2 years ago
10

The cost in dollars of producing x vehicles for a company is given by C(x)=1200x+5500

Mathematics
1 answer:
GarryVolchara [31]2 years ago
7 0

The rate of change represents the <em>variable production</em> cost rate. The <em>production</em> cost is increased in 1200 units per each <em>additional</em> manufactured car.

<h3>Interpretation of a linear function</h3>

Let be C and x the production cost and the number of vehicles produced, it there is a <em>linear</em> relationship between the two variables, then we have the following formula:

C(x) = \dot r \cdot x + C_{o} (1)

Where:

  • C_{o} - Fixed production costs.
  • \dot r - Variable production cost rate.

In a nutshell, the rate of change represents the <em>variable production</em> cost rate. The <em>production</em> cost is increased in 1200 units per each <em>additional</em> manufactured car. \blacksquare

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/8223651

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6 0
3 years ago
There were 237 people who went to a theater. Of those people, 127 arrived early and 68 arrived on time. The rest of the people a
True [87]
42 arrived late


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3 0
2 years ago
Carlos had 7¾ cups of cheese. After making 5 pizzas, he now only has 2 cups of cheese. How much cheese did Carlos use?
Musya8 [376]

Answer:

5 3/4 cups of cheese used for the pizza

Step-by-step explanation:

7 3/4 = 31/4 cups cheese to start

Two cups of cheese remaining.  2 = 8/4 cups

31/4 cups - 8/4 cups = 23/4 cups used for the pizza.

23/4 = 5 3/4 cups of cheese used for the pizza

4 0
2 years ago
Is 10/25 and 40/100 equal to 2/5
forsale [732]
Yes, they are all equal to each other
5 0
3 years ago
Read 2 more answers
I cannot solve this. I don't know how.
Pani-rosa [81]
<h3>Answer:</h3>
  • f(q) = q² -2q +3
  • f(x+h) = (x+h)² -2(x+h) +3
  • (f(x+h) -f(x))/h = 2x -2 +h
<h3>Step-by-step explanation:</h3>

The notation f(x) means you have a function that has been given the name f, and it makes use of the variable x. The variable in the parentheses is called the "argument" of the function f.

(a) To find f(q), you put q everywhere x is in the function equation. This is called evaluating the function for an argument of "q". In the following, note that we have simply changed x to q. (It's really that simple.)

... f(q) = q² -2q +3

(b) As in the previous case, we replace x with (x+h) everywhere.

... f(x+h) = (x+h)² -2(x+h) +3

You can multiply it out, but there appears to be no need to do so for this part of the question.

(c) The intent here is that f(x+h) and f(x) will be replaced by their values and the whole thing simplified. This requires you  expand the expression you see in part (b), subtract f(x), collect terms, and divide the whole thing by h. You have to make use of what you know about multiplying binomials.

We can do it in parts:

... f(x+h) = (x+h)² -2(x+h) +3

... = (x² +2xh +h²) + (-2x -2h) +3

Separating the h terms, this looks like ...

... = (x² -2x +3) + (2xh -2h +h²)

Now, we can finish the numerator part of the expression by subtracting f(x):

... f(x+h) -f(x) = (x² -2x +3) +(2xh -2h +h²) -(x² -2x +3)

You can see that the stuff in the first parentheses matches that in the last parentheses, so when we subtract the latter from the former, we get zero. We are left with only the terms containing h.

... f(x+h) -f(x) = 2xh -2h +h²

To finish up this problem, we need to divide this numerator value by the denominator h.

... (f(x+h) -f(x))/h = (2xh -2h +h²)/h

... = (2xh)/h -(2h)/h +h²/h

... = 2x -2 +h . . . . . this is the value of the expression

... (f(x+h) -f(x))/h = 2x -2 +h

4 0
3 years ago
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