Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).
By using the trigonometric identities below :
sin2x=2sinxcosx
cos2x=cos^2x-sin^2x
We substitute the trigonometric identities into (1).
2sin^2x+2sinxcosx+cos^2x-sin^2x=0
By combining like terms .
sin^2x+2sinxcosx+cos^2x=0.....(2)
The equation (2) is equivalent to the following expression (3).
(sinx+cosx)(sinx+cosx)=0 .....(3).
sinx+cosx=0
cosx=-sinx
divide both sides by cosx
1=-sinx/cosx
-1=sinx/cosx
sinx/cosx=tanx
substitute
-1=tanx
tanx=-1
tangent is negative in 2nd and 4th quadrants
tan135º=-1 (one answer)
tan315º=-1 (second answer)
Step-by-step explanation:
Please refer to the trigonometric identities used and explained above .
Answer:
Limit is 2
Step-by-step explanation:
The last term approaches zero as n approaches infinity so the fuction approaches 2.
Answer:
slope of the first line: 1
slope of the second line: 0.778
slope of the third line: 0.375
slope of the fourth line: 1.25
Step-by-step explanation:
Given two points (x1, y1) and (x2, y2), the slope of a line is computed as follows:
slope = (y2 - y1)/(x2 - x1)
Therefore,
slope of the first line: [5 - (-4)]/[4 - (-5)] = 1
slope of the second line: [5 - (-2)]/[4 - (-5)] = 0.778
slope of the third line: [2 - (-1)]/[3 - (-5)] = 0.375
slope of the fourth line: [5 - (-5)]/[4 - (-4)] = 1.25
Step-by-step explanation:
The snowplow's speed is 40 mph minus the loss from the snow, which is 1.2 mph times the depth of snow in inches.
y = 40 − 1.2x
When y = 0:
0 = 40 − 1.2x
1.2x = 40
x = 33 ⅓
The snowplow stops moving when the snow is 33 ⅓ inches deep or more.
Answer
S=3
Step-by-step explanation:
add 24 to both sides, then you subtract -42+24 take sign of the larges which is negative and youll get -6s=-18 divide -6 to both sides and you will get S=3