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VARVARA [1.3K]
3 years ago
12

Help me, please

Mathematics
2 answers:
BigorU [14]3 years ago
8 0

Answer:

41.6

Step-by-step explanation:

The area is measurement of the surface of a shape. To find the area of a rectangle or a square you need to multiply the length and the width of a rectangle or a square. Area, A, is x times y.

NISA [10]3 years ago
7 0

Answer:

20

Step-by-step explanation:

A = LW

A = 25/2 in. × 8/5 in.

A = (25 × 8)/(2 × 5) in.²

A = 200/10 in.²

A = 20 in.²

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I need help that is simple enough explnation
velikii [3]

Answer:

7 in both boxes

Step-by-step explanation:

In the picture, it shows

4 (x - 3) = 20

and then it shows

4 (x) - 4 (3) = 20

so practically you separate the x and 3 and put them in parentheses and then put a 4 next to both of them.

It should be the same as your question.

7 x (8 - 3)

and then separate 8 and 3 and put a 7 next to both of them.

( 7 x 8) - ( 7 x 3)

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
Jocelyn walks her dog 5 days each week.Each Walk is 2 1/4 miles long. What is the total number of miles that Jocelyn walks her d
igor_vitrenko [27]

Answer:the answer is c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the domain of the function
Ksenya-84 [330]

Answer:

x\geq -6

Step-by-step explanation:

The domain of a function is all of the values that x can be under that specific function. In this case, we're asking what values of x allow \sqrt{\frac{1}{3} x+2} to exist.

In order for square roots to exist, the quantity under the square root must be greater than or equal to 0, because you can't take the square root of a negative number. Therefore, we can write the following inequality to solve for x:

\frac{1}{3}x+2\geq 0

Solving this inequality, we get:

\frac{1}{3}x+2\geq 0

\frac{1}{3}x\geq -2 (Subtract 2 from both sides of the inequality to isolate x)

x\geq -6 (Multiply both sides of the inequality by 3 to get rid of x's coefficient)

Hope this helps!

8 0
3 years ago
For the function f(x)=ax^3+bx^2-5x+9, determine the values of a and b so that f(-1)=12 and f'(-1)=3
Alecsey [184]

If

<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9

then

<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5

Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations

-<em>a</em> + <em>b</em> + 5 + 9 = 12

3<em>a</em> - 2<em>b</em> - 5 = 3

or

-<em>a</em> + <em>b</em> = -2

3<em>a</em> - 2<em>b</em> = 8

Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :

2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8

-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8

<em>a</em> = 4

Substitute this into the first equation above to solve for <em>b</em> :

-4 + <em>b</em> = -2

<em>b</em> = 2

4 0
3 years ago
Is this right yes or no
posledela

Answer: yes

Step-by-step explanation: [12(1/2)+5(6)] / 3(3) = 36/9 = 4

5 0
3 years ago
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