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2 years ago

7

SOMEONE PLS HELP I WANT TO GO TO BED AND EXPLAIN HOW TO PLS

1 answer:

vlabodo [156]2 years ago

3 0

Answer:

40 degrees

Step-by-step explanation:

2x-30+x=90

Then you add x to 2x which will be 3x so now its

3x-30=90

add 30 to both sides

3x=120

divide 3 from both sides

x=40

Since Angle QPR is virticle to 2x-30+x=90

Angle QPR is 40 degrees

I got you bro go to sleep g

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Which ordered pair is a solution of the equation?<br> 7x-2y=-57x

stepladder [879]

Answer:

D Neither

Step-by-step explanation:

D neither

Hope it helps you in your learning process.

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2 years ago

An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude

AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

$p\pm z*\sqrt{\frac{p*(1-p)}{n} }$

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

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60 students were in the sample.

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3 years ago

How do you graph this equation 1/3x-1/6y=0

Lubov Fominskaja [6]

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5 0

3 years ago

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

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3 years ago

Priority question

Ymorist [56]

Sixth grade:
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5 | x x x x x
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7 | x x x x
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The range (low, high) and median of the 6th grade scores are all higher than those of the 7th grade scores.

Based on visual inspection, Grade 6 appears to have the higher mean score.

6 0

3 years ago

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