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hammer [34]
3 years ago
8

Find all numbers whose absolute value is -5.

Mathematics
2 answers:
rewona [7]3 years ago
7 0
The answer is none hope this helps
Kryger [21]3 years ago
3 0

There are none. Absolute values are always positive

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What is the result when −2/3 subtracted from −14/15?
disa [49]

Step-by-step explanation:

14/15 - 2/3 =

14/15 and 2/3 lcm is 15

so 14/15 becomes 14/15

- 2/3 become 10/15

15÷5=3 and 10÷5=2

so 14/15

-10/15=4/15

14-10 = 4

answer is 4/15 and since 15 can't be divided by 4 equally it is in simplest form at 4/15

7 0
3 years ago
a 9 pound bag of sugar is being split into containers that hold 2/3 of a pound. how many containers of sugar will the 9 pound ba
LUCKY_DIMON [66]
Namely, how many times does 2/3 go into 9?

well

\bf 9 \div \frac{2}{3}\implies \cfrac{9}{\frac{2}{3}}\implies \cfrac{\quad \frac{9}{1}\quad }{\frac{2}{3}}\implies \cfrac{9}{1}\cdot \cfrac{3}{2}\implies \cfrac{27}{2}
\\\\\\
\textit{2 goes \underline{13 times} into 27, with a \underline{remainder of 1}}\implies 13\frac{1}{2}
3 0
3 years ago
I need help please ​
IRISSAK [1]

Answer:

2,3,6,7 from the top

Step-by-step explanation:

5 0
3 years ago
Write the coordinate of G'after G(1, 2) was reflected over the line y=x.
Vikentia [17]

Answer:

(-1,2)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%283x%20%2B%204%29%20%20-%207%20log_%7B4%7D%7Bx%7D%5E%7B2%7D%20%20%2B%20%20log_%
olga2289 [7]

First of all, we need all logarithms to have the same base. So, we use the formula

\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}

To change the second term as follows:

\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}

Finally, using the property

\log(a^b)=b\log(a)

we have

\dfrac{\log_2(x^2)}{2}=\log_2(x)

So, the equation becomes

\log_2(3x+4)-7\log_2(x)+\log_2(x)=2 \iff \log_2(3x+4)-6\log_2(x)=2

We can now use the formula

\log(a)-\log(b)=\log\left(\dfrac{a}{b}\right)

to write the equation as

\log_2(3x+4)-6\log_2(x)=2 \iff \log_2(3x+4)-\log_2(x^6)=2 \iff \log_2\left(\dfrac{3x+4}{x^6}\right)=2

Now consider both sides as exponents of 2:

\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

5 0
3 years ago
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