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castortr0y [4]
1 year ago
6

a password to a computer consists of 6 characters: a digit, a letter, a digit, a letter, a digit, and a letter in that order, wh

ere the numbers from 1 through 9 are allowed for digits. how many different passwords are possible?
Mathematics
1 answer:
MrRa [10]1 year ago
4 0

As per the concept of probability, there are 4,717,440 number of passwords are possible.

Probability:

In statistics, probability refers the favorable outcome of the particular event.

Given,

A password to a computer consists of 6 characters: a digit, a letter, a digit, a letter, a digit, and a letter in that order, where the numbers from 1 through 9 are allowed for digits.

Here we need to find how many different passwords are possible.

Total number of characters = 6

According to this, each password would have

5 digits of 10 digits: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], and

one of 26 letters: [A to Z].

Here there is no repeats are allowed, and assuming only upper case letters are valid and the letter is the last character, then we can form 10*9*8*7*6 * 26 = 786,240 such passwords.

If the repetition is allowed then number of possible passwords is

786,240 * 6 = 4,717,440.

To know more about Probability here.

brainly.com/question/11234923

#SPJ4

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Step-by-step explanation:

Consider the quadratic equation, we have

ax^2+bx+c=0

Dividing the equation by a, we get

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Put \frac{c}{a} on the other side,

x^2+\frac{b}{a}x=\frac{-c}{a}

Add (\frac{b}{2a})^2 on both the sides,

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3 years ago
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Hello!

Answer:

\huge\boxed{x = 1/2, 9/2}

|2x - 5| = 4

Solve for the negative and positive expressions:

2x - 5 = 4

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Therefore, the solutions are x = 1/2 and 9/2.

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