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Ivenika [448]
3 years ago
9

Need help!!!! Please answer these equations and show your work. Thank you!!!

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
Problem 1.
Solve for x:
4 x + 3 = 19
Subtract 3 from both sides:
4 x + (3 - 3) = 19 - 3
3 - 3 = 0:
4 x = 19 - 3
19 - 3 = 16:
4 x = 16
Divide both sides of 4 x = 16 by 4:
(4 x)/4 = 16/4
4/4 = 1:
x = 16/4
The gcd of 16 and 4 is 4, so 16/4 = (4×4)/(4×1) = 4/4×4 = 4:
Answer:  x = 4

Problem 2. 

Solve for x:
(4 x)/3 + 5 = 17
Put each term in (4 x)/3 + 5 over the common denominator 3: (4 x)/3 + 5 = (4 x)/3 + 15/3:
(4 x)/3 + 15/3 = 17
(4 x)/3 + 15/3 = (4 x + 15)/3:
(4 x + 15)/3 = 17
Multiply both sides of (4 x + 15)/3 = 17 by 3:
(3 (4 x + 15))/3 = 3×17
(3 (4 x + 15))/3 = 3/3×(4 x + 15) = 4 x + 15:
4 x + 15 = 3×17
3×17 = 51:
4 x + 15 = 51
Subtract 15 from both sides:
4 x + (15 - 15) = 51 - 15
15 - 15 = 0:
4 x = 51 - 15
51 - 15 = 36:
4 x = 36
Divide both sides of 4 x = 36 by 4:
(4 x)/4 = 36/4
4/4 = 1:
x = 36/4
The gcd of 36 and 4 is 4, so 36/4 = (4×9)/(4×1) = 4/4×9 = 9:
Answer:  x = 9

Problem 3

Solve for x:
4 (6 - 2) x - 10 = 20
6 - 2 = 4:
4×4 x - 10 = 20
4×4 = 16:
16 x - 10 = 20
Add 10 to both sides:
16 x + (10 - 10) = 10 + 20
10 - 10 = 0:
16 x = 20 + 10
20 + 10 = 30:
16 x = 30
Divide both sides of 16 x = 30 by 16:
(16 x)/16 = 30/16
16/16 = 1:
x = 30/16
The gcd of 30 and 16 is 2, so 30/16 = (2×15)/(2×8) = 2/2×15/8 = 15/8:
Answer: x = 15/8

Problem 4

Solve for x:
4.3 x + 0.7 = 5
Subtract 0.7 from both sides:
4.3 x + (0.7 - 0.7) = 5 - 0.7
0.7 - 0.7 = 0:
4.3 x = 5 - 0.7
5 - 0.7 = 4.3:
4.3 x = 4.3
Divide both sides of 4.3 x = 4.3 by 4.3:
(4.3 x)/4.3 = 4.3/4.3
4.3/4.3 = 1:
x = 4.3/4.3
4.3/4.3 = 1:
Answer:  x = 1
As for the Real world question, I have no idea. Given are, $25 to turn on the electricity and $4/hr to run it.  What is she selling and for how much? I don't think there is a solution as not enough information is given.




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The percent, X , of shrinkage o n drying for a certain type of plastic clay has an average shrinkage percentage :, where paramet
never [62]

Answer:

a) t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744    

The degrees of freedom are given by:

df=n-1=45-1=44  

The critical value for this case is t_{\alpha}=1.68 since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

b) p_v =P(t_{(44)}>2.744)=0.0044  

Step-by-step explanation:

Information given

\bar X=18.4 represent the sample mean

s=2.2 represent the sample standard deviation

n=45 sample size  

\mu_o =17.5 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test if the true mean is higher than 17.5, the system of hypothesis would be:  

Null hypothesis:\mu \leq 17.5  

Alternative hypothesis:\mu > 17.5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744    

The degrees of freedom are given by:

df=n-1=45-1=44  

The critical value for this case is t_{\alpha}=1.68 since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

Part b

The p value would be given by:

p_v =P(t_{(44)}>2.744)=0.0044  

5 0
3 years ago
Solve:<br><br> (2.5x10^6) x (3x10^6)<br><br> (1.1x10^7)/(1.2x10^7)
bazaltina [42]

7.5^12

.916666666666

6 0
3 years ago
I need help is for today!!!!
kaheart [24]

Answer:

angle b = 25°

for angle A = 180 - 50 (ie 25 + 25)

angle a =130°

3 0
3 years ago
Read 2 more answers
Irene knows there are 22 cups in 11 pint. She writes the equation c=2pc2p to find the number of cups, cc, in any number of pints
Juli2301 [7.4K]
The answer is: No
Becuase the equation itself is not correct. The equation is c = 2p.
Good Luck!
4 0
3 years ago
Read 2 more answers
68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se
Mnenie [13.5K]

Answer:

\boxed{\bf\: The  \: park  \: sold  \boxed{ 34{}} \: child  \: tickets.}

Step-by-step explanation:

<u>Given:</u>

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

<u>To </u><u>Find:</u>

The Number of child tickets the park sold.

<u>Solution:</u>

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

\sf \:  =  \:  \cfrac{68}{100}  \times 50

<u>Note</u>:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: <u>Cancel One zero of 50 and one zero of 100,That is</u>:-

\sf =  \cfrac{68}{ 10\cancel0}  \times 5 \cancel0

<em>Results to,</em>

\sf  = \cfrac{68}{10}  \times 5

Step 3: <u>Cancel 5 and 10, That is</u>:-

\sf  = \cfrac{68}{ \cancel{10 }}  \times  \cancel5

<em>Results to,</em>

\sf =\:  \cfrac{68}{2}  \times 1

\sf = \cfrac{68}{2}

Step 4: <u>Cancel 68 and 2, That is</u>:-

\sf =\:  \cfrac{ \cancel{68}}{ \cancel2}

<em>Results to,</em>

\sf  =  \cfrac{34}{1}

\sf  = 34

34 is the result.

Hence,

\underline{ \rm \: The  \: park  \: sold  \: \bold{ 34 } \: child  \: tickets.}

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0
3 years ago
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