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Ivenika [448]
3 years ago
9

Need help!!!! Please answer these equations and show your work. Thank you!!!

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
Problem 1.
Solve for x:
4 x + 3 = 19
Subtract 3 from both sides:
4 x + (3 - 3) = 19 - 3
3 - 3 = 0:
4 x = 19 - 3
19 - 3 = 16:
4 x = 16
Divide both sides of 4 x = 16 by 4:
(4 x)/4 = 16/4
4/4 = 1:
x = 16/4
The gcd of 16 and 4 is 4, so 16/4 = (4×4)/(4×1) = 4/4×4 = 4:
Answer:  x = 4

Problem 2. 

Solve for x:
(4 x)/3 + 5 = 17
Put each term in (4 x)/3 + 5 over the common denominator 3: (4 x)/3 + 5 = (4 x)/3 + 15/3:
(4 x)/3 + 15/3 = 17
(4 x)/3 + 15/3 = (4 x + 15)/3:
(4 x + 15)/3 = 17
Multiply both sides of (4 x + 15)/3 = 17 by 3:
(3 (4 x + 15))/3 = 3×17
(3 (4 x + 15))/3 = 3/3×(4 x + 15) = 4 x + 15:
4 x + 15 = 3×17
3×17 = 51:
4 x + 15 = 51
Subtract 15 from both sides:
4 x + (15 - 15) = 51 - 15
15 - 15 = 0:
4 x = 51 - 15
51 - 15 = 36:
4 x = 36
Divide both sides of 4 x = 36 by 4:
(4 x)/4 = 36/4
4/4 = 1:
x = 36/4
The gcd of 36 and 4 is 4, so 36/4 = (4×9)/(4×1) = 4/4×9 = 9:
Answer:  x = 9

Problem 3

Solve for x:
4 (6 - 2) x - 10 = 20
6 - 2 = 4:
4×4 x - 10 = 20
4×4 = 16:
16 x - 10 = 20
Add 10 to both sides:
16 x + (10 - 10) = 10 + 20
10 - 10 = 0:
16 x = 20 + 10
20 + 10 = 30:
16 x = 30
Divide both sides of 16 x = 30 by 16:
(16 x)/16 = 30/16
16/16 = 1:
x = 30/16
The gcd of 30 and 16 is 2, so 30/16 = (2×15)/(2×8) = 2/2×15/8 = 15/8:
Answer: x = 15/8

Problem 4

Solve for x:
4.3 x + 0.7 = 5
Subtract 0.7 from both sides:
4.3 x + (0.7 - 0.7) = 5 - 0.7
0.7 - 0.7 = 0:
4.3 x = 5 - 0.7
5 - 0.7 = 4.3:
4.3 x = 4.3
Divide both sides of 4.3 x = 4.3 by 4.3:
(4.3 x)/4.3 = 4.3/4.3
4.3/4.3 = 1:
x = 4.3/4.3
4.3/4.3 = 1:
Answer:  x = 1
As for the Real world question, I have no idea. Given are, $25 to turn on the electricity and $4/hr to run it.  What is she selling and for how much? I don't think there is a solution as not enough information is given.




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D Question 6
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Answer:

≈ 6 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = F(2, 11) and (x₂, y₂ ) = G(5, 16)

d = \sqrt{(5-2)^2+(16-11)^2}

   = \sqrt{3^2+5^2}

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3 years ago
Given 2x = -4y + 6 find the x intercept
8_murik_8 [283]

Step-by-step explanation:

2x = -4y + 6

To find the x intercept of the equation set y = 0 that's change the value of y by zero in order to find x

That's

2x = - 4(0) + 6

2x = 6

Divide both sides by 2

x = 3

<h3>The x intercept is 3 or ( 3 , 0) </h3>

Hope this helps you

5 0
4 years ago
The mean area of homes in a certain city built in 2009 was 2438 square feet. Assume that a simple random sample of 11 homes in t
mr Goodwill [35]

Answer:

The p-value of the test is 0.029.

Step-by-step explanation:

The mean area of homes in a certain city built in 2009 was 2438 square feet.

An insurance company wants to know if the mean area of homes built in 2010 is less than that of homes built in 2009.

This means that at the null hypothesis we test if the mean is the same as in 2009, that is:

H_0: \mu = 2438

At the alternate hypothesis, we test that if it is less, than is;

H_a: \mu < 2438

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

2438 is tested at the null hypothesis:

This means that \mu = 2438

Assume that a simple random sample of 11 homes in the same city built in 2010 had a mean area of 2,293 square feet, with a standard deviation of 225 square feet.

This means that n = 11, X = 2293, s = 225

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2293 - 2438}{\frac{225}{\sqrt{11}}}

t = -2.14

Compute the P-value of the test.

Probability of finding a mean less than a value(in this case, 2293) is a one-tailed test.

The pvalue is found for a one-tailed test, with t = -2.14 and 11 - 1 = 10 degrees of freedom. With the help of a calculator, the pvalue of the test is of 0.029

The p-value of the test is 0.029.

7 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
Which of the following equations have no solutions?
Andre45 [30]

Answer:

A

Step-by-step explanation:

If the variable quantities are the same, but the constants are different, then that equation has no solutions.

4 0
3 years ago
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