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MAXImum [283]
2 years ago
6

A scientist is studying wildlife in Ohio and she estimates that the population of bats is tripling every year. If she had counte

d 3000 bats in 2017, how many will there be in 2021?
Mathematics
1 answer:
Sloan [31]2 years ago
8 0

The number of bats that there would be in 2021 would be 768,000.

<h3>What would be the number of bats in 2021?</h3>

The formula that can be used to determine the future value of bats in 2021 is:

FV = P (1 + r)^n

Where:

  • FV = Future value
  • P = Present value = 3000
  • R = interest rate = 300%
  • N = number of years = 4

3000(1 + 3)^4

3000 x 4^4 = 768,000

To learn more about future value, please check: brainly.com/question/18760477

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Answer:

z = 7

Step-by-step explanation:

Based on the midsegment theorem of a triangle, the length of the midsegment of the triangle (z) = ½ of the length of the 3rd side of the triangle (14)

Thus:

z = ½(14)

z = 7

4 0
3 years ago
Marcus has a square shaped garden that has an area of 4(x^2-y^2) square feet. If the garden has four equal sections, what is the
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x^2-y^2

Step-by-step explanation:

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2 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
What is the area of this square?
Alex73 [517]
16 bc all sides of a square are congruent and area = LxW so 4x4=16
4 0
3 years ago
A basketball player made 80 out of 100 attempted free throws. What percent of free throws was​ made?
Mrac [35]

Percent of free throws = (number of free throws made / total attempts) x 100

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The answer is 80%

5 0
3 years ago
Read 2 more answers
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