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Advocard [28]
3 years ago
14

The perimeter of a rectangular room is 60m.what is the width of the room if the length is 18m​

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

12

Step-by-step explanation:

18*2=36, 60-36=24, 24/2=12

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Determine whether each of the following are functions
Alja [10]

Answer:

xxc

Step-by-step explanation:

7 0
3 years ago
Simplify an expression for the area of a rectangle with side lengths 12 and (5/6x+23).
lesantik [10]

Answer:

10x+23 (pretty sure) and the * means multiply

Step-by-step explanation:

12*(5\6x+23)\\12*5/6x\\12/1*5/6x\\60/6x\\10x+23

4 0
3 years ago
A 50 g sample a vinegar contain 6% by mass acetic acid mixed with water. What is the mass of acetic acid in the sample?
noname [10]

Answer:

1000000000000000000p000000000000

5 0
3 years ago
I need to verify identity functions for a one to one function.
Eddi Din [679]

We have the function

f(x)=(x+6)^3

1. For f^-1:

Let y = f(x) = (x+6)^3

Switch x and y to get:

x=(y+6)^3

And solve for y

\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}

And we have y = f^-1(x)

Answer blank 1:

f^{-1}(x)=x^{\frac{1}{3}}-6

2. For f o f^-1 (x):

(f\circ f^{-1})(x)=f(f^{-1}(x))

And solve

\begin{gathered} =f(x^{\frac{1}{3}}-6) \\ =(x^{\frac{1}{3}}-6+6)^3 \\ =(x^{\frac{1}{3}})^3 \\ =x \end{gathered}

answer blank 2

x^{\frac{1}{3}}-6

answer blank 3

x^{\frac{1}{3}}-6

answer blank 4

x^{\frac{1}{3}}

3. For f^-1 o f:

(f^{-1}\circ f)(x)=f^{-1}(f(x))

Solve

\begin{gathered} =f^{-1}((x+6)^3) \\ =\sqrt[3]{(x+6)^3}-6 \\ =x+6-6 \\ =x \end{gathered}

answer blank 5

(x+6)^3

answer blank 6

(x+6)^3

answer blank 7

x+6

4 0
1 year ago
2x + 4y = 16<br> 3x - 2y = 8<br> solve using SUBSTITUTION METHOD ONLY!<br><br> PLS ANSWER QUICK !!!
Savatey [412]

Answer:

x = 4, y = 2

Step-by-step explanation:

3x - 2y = 8

-2y = -3x + 8

y = 3/2x - 4

2x + 4(3/2x - 4) = 16

2x + 6x - 16 = 16

8x = 32

x = 4  

3(4) - 2y = 8

12 - 2y = 8

-2y = -4

y = 2

5 0
3 years ago
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