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3 years ago

find an equation for the line parallel to y=3x-2 with y- intercept (0,4). write the answer in the slope intercept form

1 answer:

7 0

Parallel lines have same same slope with different c values. comparing the given equation to y=mx+c. m=3 and c=-2. for the parallel line the c is different.

now apply the values of (0,4) in the equation y=3x+c and solving for C gives
the REQUIRED LINE EQUATION as y=3x+4

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Answer:

c, the third answer

Step-by-step explanation:

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3 years ago

Show that x+y:x-y=3:2

ycow [4]

We have,

x+y:x-y=3:2

To prove that, x+ y : x - y = 3:2.

x+y=3

And,

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x+y+x-y=3+2

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x+y:x-y=

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50 POINTS/ WILL MARK BRAINLIEST

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Answer:

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3 years ago

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3 years ago

A study was conducted to compare the proportion of drivers in Boston and New York who wore seat belts while driving. Data were c

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(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

A.)

According to given data find the test statistic for this test using Ha:

p1 = 0.581

p2 = 0.832

standard error = SE = 0.116

<h3>Test statistics :-</h3>

Z = $\frac{p1 - p2}{SE}$

Z = $\frac{0.581 - 0.832}{0.116}$ = -2.164

Z = -2.164

B.)

According to given Determine the p-value (3 decimal places).

<h3>p - value</h3>

it is left tailed test.

p - value for left tailed test is,

p - value = P(Z < test statistics )

p - value = P(Z < -2.164)

P - value = 0.015

C.)

Based on this p-value, which of the following would you expect for a 95%

confidence level = 95% = 0.95

significance level = α = 0.05

P -value is less than 0.05

so, reject null hypothesis at α = 0.05

That is $P_{B}$ < $P_{NY}$

so, based on P - value , All values in the 95% confidence interval

PB - PNY is negative.

D.)

According to given data What is the correct conclusion?

Reject null hypothesis at α = 0.05

so, $P_{B}$ < $P_{NY}$

Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

know more about test statics visit this link

brainly.com/question/23332597

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