find an equation for the line parallel to y=3x-2 with y- intercept (0,4). write the answer in the slope intercept form

1 answer:

7 0

Parallel lines have same same slope with different c values. comparing the given equation to y=mx+c. m=3 and c=-2. for the parallel line the c is different.

now apply the values of (0,4) in the equation y=3x+c and solving for C gives
the REQUIRED LINE EQUATION as y=3x+4

You might be interested in

Please help! Will mark brainliest! Simplify. <img src="https://tex.z-dn.net/?f=%283a%5E%7B2%7D%2A-3a%29" id="TexFormula1" ti

PilotLPTM [1.2K]

Step-by-step explanation:

Since -3a can be said to have a power of 1, we add the powers together and multiply the coefficients

-9a³

8 0

3 years ago

-90d = 9 What is d??

qaws [65]

D= -10
explanation:
-90/9=-10

8 0

3 years ago

Read 2 more answers

PLZZZZZZZ HELP ASAP Figure JKL is reflected about the y-axis to obtain figure J’K’L’: A coordinate plane is shown. Triangle JKL

Ierofanga [76]

Answer:

A i think

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How many tens do you need to get too 805

Goryan [66]

The answer is 80.5 ... 805 / 5

7 0

3 years ago

Read 2 more answers

In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 8x^3+2/2x^3+x

KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a vertical asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) $y=\frac{8}{2}=4$

6 0

3 years ago