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d1i1m1o1n [39]
3 years ago
5

I need help! this question is from my iready eighth grade test and I don’t understand it!!

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0
It should be the 2 one
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The solution for x2+2x+8<0
Tema [17]
Answer for this question is the zeros are greater than -4 and 2
7 0
4 years ago
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Dan has the same number of nickels and dimes in his piggy bank. If the total amount of those coins is $0.90, how many of each co
Karolina [17]

Hello There!

<u><em>n - d = 0</em></u>

<u><em>5n+10d = 90</em></u>

<u><em>----------------------</em></u>

<u><em>n-d = 0</em></u>

<u><em>n+2d = 18</em></u>

<u><em>-------------------</em></u>

<u><em>Subtract and solve for "d":</em></u>

<u><em>3d = 18</em></u>

<u><em>d = 6 (# of dimes)</em></u>

<u><em>n = d = 6 (# of nickels)</em></u>

8 0
3 years ago
What is the area of the irregular polygon below
garik1379 [7]

Answer:

The answer is 121.5 sq. units.

Step-by-step explanation:

To find the answer,

Area of Pentagon: About 61.5 sq. units

Area of Rectangle: 60 sq. units

61.95 + 60 = 121.5 sq. units

Thanks, I hope I got this right!

3 0
3 years ago
Read 2 more answers
Please help asap!
lidiya [134]
You would distribute, 300 times 80 is 2400 and -3x times 1x is -3x so the equation would be y=2400-3x
8 0
3 years ago
In a bag of sweets, 6 are orange and 9 are lime. Jodi chooses a sweet at random, eats it an
Digiron [165]

Answer:\frac{17}{35}

Step-by-step explanation:

Given

The bag contains 6 orange and 9 lime sweets

For both sweets of the same flavor, Jodi must either choose orange or lime

No. of ways it can be done is ^6C_1\times^5C_1+^9C_1\times^8C_1

The total no of ways of selecting two sweets out of 15 is ^{15}C_1\times^{14}C_1

The probability that both sweets are the same flavor

P=\dfrac{^6C_1\times^5C_1+^9C_1\times^8C_1}{^{15}C_1\times^{14}C_1}=\frac{102}{210}=\frac{51}{105}=\frac{17}{35}

3 0
3 years ago
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