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3 years ago

HELP PLEASE!! NUMBER 6!!

Mathematics

1 answer:

KiRa [710]3 years ago

4 0

Answer:

hey it's not clear....

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I need help with this what’s the answer

Dovator [93]

Answer:

Step-by-step explanation:

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3 years ago

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HELP PLEASE!!! (Angle) JNM = 103. Find (angle) JNK.

sleet_krkn [62]

Answer:

Angles KNL and JNM are vertical angles so they are equal so

10y - 12 = 8y + 4

2y = 16

y = 8

So angle KNL = 10y - 12 = 10(8) - 12 = 80 - 12 = 68�

and, as a check

Angle JNM = 8y + 4 = 8(8) + 4 = 64 + 4 = 68�

Step-by-step explanation:

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3 years ago

How many zeros are in the simplified expression 4 times 10

Zinaida [17]

The answer is c. x+1 (I'm pretty sure)

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4 years ago

Hi! I've tried this problem a couple times but am still stumped :( Can you help?!

aniked [119]

ANSWER:

$X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

EXPLANATION:

Given:

$U\text{ = }\begin{bmatrix}{1} & {3} & {-5} \\ {2} & {14} & {11} \\ {-8} & {0} & {5}\end{bmatrix}\text{ V =}\begin{bmatrix}{13} & {1} & {-7} \\ {-6} & {1} & {9} \\ {0} & {15} & {23}\end{bmatrix}$

Since U and V are Matrices with equal dimensions(3 x 3 matrix), and

X + U = V.

To solve for X, we have:

X = V - U

$\begin{gathered} X\text{ = V - U} \\ X\text{ = }\begin{bmatrix}{13-1} & {-1-3} & {-7-(-5)} \\ {-6-2} & {1-14} & {19-11} \\ {0-(-8)} & {15-0} & {23-5}\end{bmatrix}=\text{ }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix} \end{gathered}$ $X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

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1 year ago

A division problem is shown below. 4 and one-third divided by 5 and StartFraction 1 over 6 EndFraction The reciprocal of a fract

natulia [17]

Answer:

To sum it up, Iit's C.

Step-by-step explanation:

6 0

3 years ago

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