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dezoksy [38]
4 years ago
11

The sales tax on an item selling for $20 is 3% What is the total

Mathematics
2 answers:
kupik [55]4 years ago
8 0
3% of 20 is 0.6 which you can find by doing 20*0.03. Adding 0.6 (your 30% tax) to 20 gives you $20.60.
SCORPION-xisa [38]4 years ago
6 0

Answer: $20.60

Step-by-step explanation:

20 × 3% = .60

20 + .60 = 20.60

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Form a polynomial whose factors are (x+1) , (x+2) and (x-3)​
N76 [4]

Answer:

x³-7x-6

Step-by-step explanation:

Find the products of the factors

(x+1)(x+2)(x-3)

x²+3x+2(x-3)

x³+3x²+2x-3x²-9x-6

x³-7x-6

6 0
3 years ago
Which sum is equal to the expression - 5x3 + 2x2 + 9x+2/<br> (x²+ 2)²
Makovka662 [10]

Answer:

Option C

Step-by-step explanation:

Given expression is \frac{-5x^3+2x^2+9x+2}{(x^2+2)^2}

Option A

\frac{A}{x^2+2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{A(x^2+2)}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{Ax^2+2A+Bx+C}{(x^2+2)^2}

Numerator is a quadratic polynomial, while the expression has the numerator as a cubic .

Therefore, both the expressions are not equivalent.

Option B

\frac{A}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{A+Bx+C}{(x^2+2)^2}

Here, numerator of the expression is a linear polynomial which is not equal to given expression.

Therefore, both the expressions are not equivalent.

Option C

\frac{Ax+B}{(x^2+2)}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{(Ax+B)(x^2+2)}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+2Ax+2B+Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+x(2A+C)+D}{(x^2+2)^2}

Here, numerator is a cubic polynomial.

Therefore, both the expressions are equivalent.

Option D

\frac{Ax+B}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{x(A+C)+(B+D)}{(x^2+2)^2}

Numerator is a linear polynomial.

Therefore, sum is not equal to the given expression.

Option C will be the answer.

3 0
3 years ago
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Vikki [24]

Answer:

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Step-by-step explanation:

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As a result, we can say that the area of \triangle A,  \triangle B,  \triangle C are equal.

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