Answer:
Area of 
ACD = 4 
Area of ABC = 16
Step-by-step explanation:
Given that:
D is a point on AB.
and ABC is a triangle.
AD:DB = 1 : 3
Area of CDB = 12
Kindly refer to the attached image as per the given dimensions and values.
To find:
Area of ACD and Area of ABC = ?
Solution:
Formula for area of a triangle = 
The altitudes of triangles CDB and ACD are equal in dimensions.
Therefore the area of triangles CDB and ACD will be equal to the ratio of their bases.
Area of ACD : Area of CDB = AD: DB = 1 : 3
Area of ACD = 
Area of ABC = Area of ACD + Area of CDB = 12 + 4 = <em>16</em>
Therefore, the answer is:
Area of ACD = 4
Area of ABC = 16
Whole number = 1, 2, 3, 4, 5, 6, 7, 8, ...
6
= 6.86 ≈ 7
The most basic way to decompose a fraction is to break it into unit fractions which is when the numerator (the top number) is 1. 5/8 is the same as the unit fraction 1/8 five times
The answer is -16 your welcome
so these two lines intersect at x = 3 hmmmm what's the y-coordinate of the second line at that point?
so the y-coordinate of that second line is 0, so the point there is (3, 0) then.
so the first line is, a line that has a slope of 2 and passes through (3, 0).
