Answer:
It is 14130 mm^3
Step-by-step explanation:
So the equation for the volume of a sphere is (4/3) (3.14) r^3. So since we already have the radius, we just plug it in to get the answer:
(4/3) (3.14) r^3
(4/3) (3.14) 15^3
(4/3) (3.14) 3375
(4/3) (10597.5)
14130 mm^3
Answer:
Remember, a basis for the row space of a matrix A is the set of rows different of zero of the echelon form of A.
We need to find the echelon form of the matrix augmented matrix of the system A2x=b2
We apply row operations:
1.
- To row 2 we subtract row 1, 4 times.
- To row 3 we subtract row 1, 7 times.
- To row 4 we subtract row 1, 3 times.
- To row 5 we subtract row 1, 6 times.
- To row 6 we subtract row 1, 9 times.
We obtain the matrix
2.
- We subtract row two twice to row three of the previous matrix.
- we subtract 4/3 from row two to row 4.
- we subtract 7/3 from row two to row 5.
- we subtract 10/3 from row two to row 6.
We obtain the matrix
3.
we exchange rows three and four of the previous matrix and obtain the echelon form of the augmented matrix.
Since the only nonzero rows of the augmented matrix of the coefficient matrix are the first three, then the set
is a basis for Row (A2)
Now, observe that the last two rows of the echelon form of the augmented matrix have the last coordinate different of zero. Then, the system is inconsistent. This means that the system has no solutions.
The median is 5 because its the middle number you got 3 3 5 9 11
Answer:
5
Step-by-step explanation: