Answer:
<em>7.2 N</em>
Explanation:
length of wire L = 240 m
current I = 500 A
field strength B = 3 x 10^-5 T
magnetic force on a current carrying conductor F is given as
F = BILsin∅
The wires are perpendicular with field therefore sin∅ = sin 90° = 1
therefore,
F = BIL = 3 x 10^-5 X 500 X 240 = 3.6 N
<em>If the wire exists between this two transmission lines, then total magnetic force on the wire = 2 x 3.6 = 7.2 N</em>
Answer:
The average angular acceleration of the skater is <u>0.98 rad/s²</u>.
Explanation:
Given:
Initial angular speed of the skater is,
Final angular speed of the skater is,
Time interval for the change is,
We know that, average angular acceleration is given as the ratio of change of angular speed and the time interval.
Therefore, the average angular acceleration is given as:
Hence, the average angular acceleration of the skater is 0.98 rad/s².
To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.
PART A) We will begin by finding the two net distances.
And the distance 'd' is
Through the free-body diagram the tension components are given by
Here we can watch that,
Dividing both expression we have that,
Replacing the values,
PART B) Using the vertical component we can find the tension,