Answer:
Option B. N2(g) + 3H2(g) → 2NH3(g)
Explanation:
When nitrogen react with hydrogen, they form a product as shown below:
N2+ H2 → NH3
We need to balance the equation. This is illustrated below:
There are 2 atoms of nitrogen on the left side and 1 atom on the right side. To balance it, put 2 in front of NH3 as shown below:
N2+ H2 → 2NH3
Now, There are a total of 6 atoms of Hydrogen on the right side and 2 atoms on the left side side. This can be balanced by putting 3 in front of H2 as shown below:
N2+ 3H2 → 2NH3
Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation
The mass of a substance is given in atomic mass units and is calculated by adding the average atomic masses of all the atoms in the substance's chemical formula.
<h3>What empirical formula represents the total average atomic mass of every atom?</h3>
The Method The average atomic masses of all the atoms included in a formula's representation are added to get the mass of any molecule, formula unit, or ion. It has no bearing on the number of significant figures because the number of atoms is an exact quantity. One H2O molecule weighs 18.02 amu on average.
<h3>What connection exists between the empirical formula and the molecular formula?</h3>
You can determine the number of atoms of each element in a molecule using its molecular formula. These empirical formulations provide the most basic or reduced elemental ratio of a compound. The empirical formula and the molecular formula of a substance are same if the molecular formula can no longer be decreased.
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I believe it's DNA.
Here're some sentences to explain:
Genetic material, also known as deoxyribonucleic acid<span> (</span>DNA<span>) and </span>Ribonucleic acid<span> (</span>RNA<span>), plays a fundamental role in the composition of living organisms.</span>
Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes = 
Distance, d = 2500 km = 
Speed of propagation, s = 
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:

t = 10 ms
- In general, propagation time, t is given by:

- No, this delay is independent of the length of the packet.
- No, this delay is independent of the rate of transmission.
Low. Copper has relatively high conductivity.