Ask question

Ask question

All categories

3 years ago

13

Odina walked down the hall at school from the cafeteria to the band room, a distance of 100.0m. A class of physics students

2 answers:

Nata [24]3 years ago

7 0

Find distance she traveled:

100m -25m = 75m

58 seconds / 2 second intervals = 29

29 x 2.6m = 75.4 meters total.

if the distance wasn’t rounded the statement was False.

Answer: False

Stolb23 [73]3 years ago

7 0

The answer of this question is t

You might be interested in

A bullet with a mass of 5.00 x 10^-3 kg is loaded into a gun. The loaded gun has a mass of 0.52 kg. The bullet is fired, causing

beks73 [17]

For the answer to the question above,
220 m/s
<span>mass of the bullet * velocity of the bullet = mass of the gun * velocity of the gun </span>
<span>0.005 kg * v = 0.52 kg * 2.1 m/s </span>
<span>-> v = (0.52kg * 2.1 m/s) / 0.005 kg = 218.4 m/s
</span>I hope my answer helped you. Have a nice day!

3 0

4 years ago

A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia

aivan3 [116]

Answer:

$\Delta V=V_{2}-V_{1}=45.4V$

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

$E=\frac{1}{2} CV^{2}$

$V=\sqrt{2E/C}$

If we increase the Voltage, the Energy increase also:

$V_{1}=\sqrt{2E_{1}/C}$

$V_{2}=\sqrt{2E_{2}/C}$

The voltage difference:

$V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}$

$V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V$

5 0

3 years ago

During a very quick stop, a car decelerates at 28.4 rad/s?. Assume the tires initially rotated in the positive direction and rad

Damm [24]

Answer:

a) 24

b) 3.3 sec

c) 29.8 m/s

d) 48.85 m

Explanation:

a)

α = angular acceleration = - 28.4 rad/s²

r = radius of the tire = 0.32 m

w₀ = initial angular velocity = 93 rad/s

w = final angular velocity = 0 rad/s

θ = angular displacement

Using the equation

w² = w₀² + 2αθ

0² = 93² + 2 (- 28.4) θ

θ = 152.3 rad

n = number of revolutions

Number of revolutions are given as

$n = \frac{\theta }{2\pi }$

$n = \frac{152.3 }{2(3.14) }$

$n = 24$

b)

t = time taken to stop

using the equation

w = w₀ + αt

0 = 93 + (- 28.4) t

t = 3.3 sec

c)

v₀ = initial velocity of the car

initial velocity of the car is given as

v₀ = r w₀ = (0.32) (93) = 29.8 m/s

d)

v = final velocity = 0 m/s

a = linear acceleration = rα = (0.32) (- 28.4) = - 9.09 m/s²

d = distance traveled by car before stopping

Using the equation

v² = v₀² + 2 a d

0² = 29.8² + 2 (- 9.09) d

d = 48.85 m

8 0

4 years ago

A closed box is filled with dry ice at a temperature of -94.7°C, while the outside temperature is 26.8°C. The box is cubical, me

Nikitich [7]

Answer:

Explanation:

3.64 x 10⁶ J passes through 6 walls

heat energy passing through 1 wall = 0.606 x 10⁶ J

Surface Area of 1 wall A = .285² = 0.081225 m²

Temperature Difference = T₁ - T₂ = 26.8 + 94.7 = 121.5

Thickness of wall d = 3.75 x 10⁻² m

Rate of heat flow per second R = $\frac{0.606 \times10^6}{24\times60\times60}$

=7.01 J per s.

Formula for rate of heat flow

R = $\frac{KA(T_1-T_2)}{d}$

Where K is thermal conductivity.

7.01 = $\frac{K\times121.5\times.081225}{3.75\times10^{-2}}$

K = 2.66 X 10⁻² W m⁻¹s⁻¹

8 0

3 years ago

In which direction does the electric field point at a position directly ((north))of a

Veseljchak [2.6K]

B. North, was the correct answer

5 0

3 years ago