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myrzilka [38]
3 years ago
10

Last year, Forest Products issued both 5-year and 10-year bonds at par. The bonds each have a coupon rate of 5.5 percent, paid s

emiannually, and a face value of $1,000. Assume the yield to maturity on each of these bonds is now 7.4 percent. What is the percentage change in the price of the 5-year bond since it was issued
Business
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

Price at issuance is $1,000 for both bonds.

Price of the 5 year bond after the market rate increased to 7.4% is:

PV of face value = $1,000 / (1 + 3.7%)⁸ = $747.77

PV of coupon payments = $27.50 x 6.81694 (PV annuity factor, 3.7%, 8 periods) = $187.47

Market price = $935.24

this bond's price decreased by 64.76/1,000 = 0.06476 = 6.48%

Price of the 10 year bond after the market rate increased to 7.4% is:

PV of face value = $1,000 / (1 + 3.7%)¹⁸ = $519.97

PV of coupon payments = $27.50 x 12.97365 (PV annuity factor, 3.7%, 18 periods) = $356.78

Market price = $876.75

this bond's price decreased by 123.25/1,000 = 0.12325 = 12.33%

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8 0
3 years ago
Read 2 more answers
when calculating net price, why do you think loans are not deducted from sticker price even if they are typically offered to you
storchak [24]

The reason loans are not deducted from sticker price even if they are typically offered to you in a financial aid package is that "the net price is actual money that you or any individual will be paying."

This is evident because a net price is the sticker price minus the student's financial aid, scholarships, grants, and other support.

Unlike sticker price, the net price is the college student's amount would eventually pay in his college years.

A sticker price is the whole amount of the annual or session cost of a college education.

Hence, in this case, it is concluded that college students should concentrate more on the net price instead of a sticker price.

Learn more here: brainly.com/question/20635459

3 0
3 years ago
At its date of​ incorporation, McCarty Company issued​ 100,000 shares of its​ $10 par common stock at​ $11 per share. During the
Paul [167]

Answer:

(C) Decrease No effect

Explanation:

at purchase:

30,000 shares x 16 dollars each:

Treasury stock  480,000 debit

              Cash              480,000 credit

--purchase of own share--

Then we will decrease retained earnings for the difference in the cash proceed on the sale and our treasury stock.

30,000 x 12 dollars = 360,000 cash proceeds

treasury stock             480,000

decrease in RE            120,000

cash                         360,000 debit

retained earnings    120,000 debit

        Treasury Stock                      480,000 credit

8 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
4 years ago
What would be you KPIs as the finance and human Resource officer?
Debora [2.8K]

Answer:

1.37 - 1.90

Explanation:

Really hard to say a exact number but here's and idea.

6 0
3 years ago
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