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MAVERICK [17]
2 years ago
5

Mrs.Kunkleman asks her students to write the Pythagorean theorem in their own words

Mathematics
1 answer:
masha68 [24]2 years ago
5 0

Step-by-step explanation:

The Pythagorean theorem can be understood as a mathematical relationship between the sides of a right triangle that helps to understand geometric problems in real situations, such as finding measurements, calculating areas, etc.

The theorem says that the square of the hypotenuse is equal to the sum of the squares on the other sides.

In a right triangle the hypotenuse is the longest side of the triangle, on the side opposite to its longest angle, and the other two sides will be the sides. So the Pythagorean theorem formula is:

a² = b² + c²

where a represents the hypotenuse and b and c the other sides.

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Find the simplified ratio of 300ml in 5 minutes
andriy [413]
300ml in 5 min can be written as a fraction 300ml/5min or 300/5 ml per min. 300/5 is the same as 60/1

So 300ml / 5min = 60ml/1min
6 0
3 years ago
Help plz i will give brainliest
jasenka [17]

Answer:

12

(If needed explanation ask in the comments! ty)

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6 0
2 years ago
it cost $270 for three people to go fishing on a fishing trip how much does it cost for 10 people to go on a fishing trip ​
coldgirl [10]

Answer:

900$

Step-by-step explanation:

270/3= 90$ per person

90*10=900$ for 10 people

6 0
3 years ago
What is the slope of the line that contains the pionts (2,3) (2,-4)​
Free_Kalibri [48]

Answer:

There is no slope

Step-by-step explanation:

If the x-coordinates are the same, then that means there's no slope and is a straight vertical line.

6 0
2 years ago
Line Segment DE is parallel to side BC of right triangle ABC. CD = 3, DE = 6, and EB = 4. Compute the area of quadrilateral BCDE
dybincka [34]

The area of quadrilateral BCDE = 20.4 sq. units

Let AD = x and AE = y.

Since ΔABC and ΔAED are similar right angled triangles, we have that

AC/AD = AB/AE

AC = AD + CD

= x + 3.

Also, AB = AE + EB

= y + 4

So, AC/AD = AB/AE

(x + 3)/x = (y + 4)/y

Cross-multiplying, we have

y(x + 3) = x(y + 4)

Expanding the brackets, we have

xy + 3y = xy + 4x

3y = 4x

y = 4x/3

In ΔAED, AD² + AE² = DE².

So, x² + y² = 6²

Substituting y = 4x/3 into the equation, we have

x² + y² = 6²

x² + (4x/3)² = 6²

x² + 16x²/9 = 36

(9x² + 16x²)/9 = 36

25x²/9 = 36

Multiplying both sides by 9/25, we have

x² = 36 × 9/25

Taking square root of both sides, we have

x = √(36 × 9/25)

x = 6 × 3/5

x = 18/5

x = 3.6

Since y = 4x/3,

Substituting x into the equation, we have

y = 4 × 3.6/3

y = 4.8

To find the area of quadrilateral BCDE, we subtract the area of ΔAED from area of ΔABC.

So, area of quadrilateral BCDE = area of ΔABC - area of ΔAED

area of ΔABC = 1/2 AC × AB

= 1/2 (x + 3)(y + 4)

= 1/2(3.6 + 3)(4.8 + 4)

= 1/2 × (6.6)(8.8)

= 1/2 × 58.08

= 29.04  square units

area of ΔAED = 1/2 AD × AE

= 1/2xy

= 1/2 × 3.6 × 4.8

= 1/2 × 17.28

= 8.64 square units

area of quadrilateral BCDE = area of ΔABC - area of ΔAED

area of quadrilateral BCDE = 29.04 sq units - 8.64 sq units

area of quadrilateral BCDE = 20.4 sq. units

So, the area of quadrilateral BCDE = 20.4 sq. units

Learn more about area of a quadrilateral here:

brainly.com/question/19678935

4 0
2 years ago
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