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GarryVolchara [31]
3 years ago
12

The ground temperature at airport is 12 degrees. The temperature decreases by 5.2 degrees for every mile above ground. What woul

d be temperature outside plane located at 3 miles above the airport
Mathematics
1 answer:
algol133 years ago
7 0

Answer:

The outside plane located at 3 miles above the airport is of -3.6 degrees.

Step-by-step explanation:

The ground temperature at airport is 12 degrees. The temperature decreases by 5.2 degrees for every mile above ground.

This means that the temperature in n miles above ground is given by:

T(n) = 12 - 5.2n

What would be temperature outside plane located at 3 miles above the airport

This is T(3). So

T(3) = 12 - 5.2*3 = 12 - 15.6 = -3.6

The outside plane located at 3 miles above the airport is of -3.6 degrees.

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Which transformations are needed to change the parent cosine function to y = 0.35 cosine (8 (x minus startfraction pi over 4 end
Nataliya [291]

The transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

  • vertical stretch of 0.35
  • horizontal compression of period of \dfrac{\pi}{4}
  • phase shift of  \dfrac{\pi}{4} to right

<h3>How does transformation of a function happens?</h3>

The transformation of a function may involve any change.

Usually, these can be shift horizontally (by transforming inputs) or vertically (by transforming output), stretching (multiplying outputs or inputs) etc.

If the original function is y=f(x)A, assuming horizontal axis is input axis and vertical is for outputs, then:

  • Horizontal shift (also called phase shift):y=f(x+c)
  1. Left shift by c units: earlier)
  2. Right shift by c units: y=f(x-c) output, but c units late)
  • Vertical shift:
  1. Up by d units: y=f(x)+d
  2. Down by d units: y=f(x)-d
  • Stretching:
  1. Vertical stretch by a factor k: y=k\times f(x)
  2. Horizontal stretch by a factor k: y=f(\dfrac{x}{k})}

For this case, we're specified that:

y = cos(x) (the parent cosine function) was transformed to

y=0.35cos(8(x-\pi/4)

We can see its vertical stretch by 0.35, right shift by horizontal stretch by 1/8

Period of cos(x) is of  length. But 1.8 stretching makes its period shrink to

\dfrac{2\pi}{8}=\dfrac{\pi}{4}

Thus, the transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

vertical stretch of 0.35

horizontal compression to period of  (which means period of cosine is shrunk to  which originally was  )

phase shift of  to right

Learn more about transformation of functions here:

brainly.com/question/17006186

7 0
3 years ago
Write in slope-intercept form an equation of the line that passes through the given points. When the points are, (-1,4) and (3,8
guajiro [1.7K]
I find it easiest to start with the 2-point form of the equation of a line.
  y = (y₂-y₁)/(x₂-x₁)*(x-x₁) +y₁
where the given points are (x₁, y₁) and (x₂, y₂).

Substituting the given numbers, you have
  y = (8 -4)/(3 -(-1))*(x -(-1)) +4
  y = 4/4(x +1) +4
  y = x +5

The desired slope-intercept form of the equation for the line is ...
  y = x + 5

5 0
4 years ago
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F(x) = x/ (x^2 + 4x - 21)<br> how do i find the domain and range?
Igoryamba

Answer:

Step-by-step explanation:

F(x) = x/ (x^2 + 4x - 21)

F(x)= x / (x - 3)(x + 7)

When x = 3 and x = -7 the denominator is zero  so there are no values of the function corresponding to these values of x.

The domain is all Real x except x = -7 and x = 3.

The range is all values of f(x) except for those values when x = -7 and x = 3.

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Laura is the fund-raising manager for a local charity. She is ordering caps for an upcoming charity walk. The company that makes
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Let number of caps =x

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let us make an inequality equation here,

Since amount cannot be greater than 1000 , so

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6x≤975

x≤162.5

rounding off ,

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So she can buy maximum 163 caps

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4 years ago
Idk how to do this! Pls help me! I need to hurry!
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I did know of the understanding of math high school?
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