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aleksandrvk [35]
3 years ago
9

Please answer missing boxes in order please ASAP will give 10 points

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

326 x 52 is the factors of the problem.

Step-by-step explanation:

To solve this problem, we need to figure out what number multiplied by what numbers is 652 and 16300. The first product (652) is made by 2 and a number. We can divide 652 by 2 to figure out this number. 652 / 2 = 326. The missing digit of the first factor is 2 making the factor 326. However, the second factor has a missing digit, too. 326 multiplied by a number has to equal 16,300. We can also solve this with division. 16,300 / 326 = 50. The missing digit has a value of 50 making the factor 52. 326 x 52 is the factors of the problem.

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which of the following statements best describes midpoint of a line segment? 1. point at end of line segments 2. a point halfway
BARSIC [14]
<h2>Hello!</h2>

The answer is:

2. A point halfway between the endpoints of a line segment.

<h2>Why?</h2>

The midpoint of a line segment, is a point that divides the line segment into two equal length sides, no matter the length of the segment, the midpoint will always cut the segment into two equal length sides

The midpoint is an ordinary point located in the middle of the line segment. The x-coordinate of the midpoint is halfway between the x-coordinates of the beginning and the end of the segment. The y-coordinate of the midpoint is halfway between the y-coordinates of the beginning and the end of the segment.

Hence, the correct option is:

2. A point halfway between the endpoints of a line segment.

Have a nice day!

8 0
3 years ago
Out of the 21 students in Terry's class, 15 prefer spaghetti over meatloaf. There are 420 students in Terry's middle school. Bas
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Answer:

300 can be expected to prefer spaghetti over meatloaf.

8 0
3 years ago
Read 2 more answers
Dos niños brincan en dos trampolines. El primer niño rebota 1.5 veces más alto que el segundo. La rapidez inicial del segundo ni
luda_lava [24]

Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.

-------------------------

  • Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.

El primer niño rebota <u>1.5 veces más alto que el segundo</u>.

O sea:

x = 1.5y

La rapidez inicial del segundo niño es de 3.3 m/s.

Esto implica que y = 3.3

¿Cuál es la rapidez (m/s) inicial del primer niño?

x = 1.5y = 1.5(3.3) = 4.95

La rapidez inicial del primer ninõ es 4.95 m/s.

Un problema similar es dado en brainly.com/question/24646137

3 0
3 years ago
Solve rational Equation <br><br> Please Show Full Steps Please!
pochemuha

Answer:

x=1

Step-by-step

Step 1:

Simplify x/x2

Dividing exponential expressions :  

1.1    x1 divided by x2 = x(1 - 2) = x(-1) = 1/x1 = 1/

Equation at the end of step 1:

  2    1         1

 (((—+1)-—)-1)-((2•—)-1)  = 0

    x    x         x

STEP 2:Rewriting the whole as an Equivalent Fraction:

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1     1 • x

   1 =  —  =  —————

        1       x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 - (x)     2 - x

——— = ———  

   x          x  

Equation at the end of step 2:

2    1     (2-x)

 (((—+1)-—)-1)-—————  = 0

    x    x       x  

STEP 3:

Simplify 1/x

Equation at the end of step 3:

2          1           (2 - x)

 (((— +  1) -  —) -  1) -  ———————  = 0

    x          x              x  

STEP4:

Simplify: 2/x

Equation at the end of step 4:

    2          1                 (2 - x)

 (((— +  1) -  —) -  1) -  ———————  = 0

    x          x                      x  

STEP 5:

Rewriting the whole as an Equivalent Fraction :

5.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1         1 • x

   1 =  —  =  —————

        1            x  

Adding fractions that have a common denominator :

5.2       Adding up the two equivalent fractions

2 + x                x + 2

—————  =  —————

  x                       x  

Equation at the end of step 5:

(x + 2)    1                                (2 - x)

 ((——————— -  —) -  1) -  ———————  = 0

      x       x                                  x  

STEP 6:Adding fractions which have a common denominator :

Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(x+2) - (1)                            x + 1

———————————  =  —————

     x                                       x

Equation at the end of step 6:

  (x + 1)                           (2 - x)

 (——————— -  1) -  ———————  = 0

     x                               x

STEP 7:

Rewriting the whole as an Equivalent Fraction :

7.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1     1 • x

   1 =  —  =  —————

        1       x  

Adding fractions that have a common denominator :

7.2       Adding up the two equivalent fractions

(x+1) - (x)                           1

———————————  =  —

     x                                   x

Equation at the end of step 7:

 1       (2 - x)

 — -  ———————  = 0

 x         x

STEP 8:

Adding fractions which have a common denominator :

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 - ((2-x))                              x - 1

———————————  =  —————

     x                                     x    

Equation at the end of step 8:

 x - 1

 —————  = 0

   x  

STEP 9:

When a fraction equals zero :

9.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 x-1

 ——— • x = 0 • x

  x

Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  x-1  = 0

.2      Solve  :    x-1 = 0

Add  1  to both sides of the equation :

                     x = 1

One solution was found :

x = 1

   

8 0
3 years ago
What is the standard form? 8x^2 + 2x^3
daser333 [38]

Answer:

..........

Step-by-step explanation:

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