Given that the triangles shown below are simiar, what is the value of x?
1 answer:
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Answer:
x = 3 ± 2
Step-by-step explanation:
given
x² - 6x + 1 = 0 ( subtract 1 from both sides )
x² - 6x = - 1
To complete the square
add (half the coefficient of the x- term)² to both sides
x² - 6x + (- 3)² = - 1 + (- 3)²
x² - 6x + 9 = - 1 + 9
(x - 3)² = 8 ( take the square root of both sides )
x - 3 = ± = ± 2
( add 3 to both sides )
x = 3 ± 2