Answer:
P'Q' is equal in length to PQ.
Step-by-step explanation:
Before rotation
P(-5, 3)
Q(-1, 3)
we get the length
L = √((-1-(-5))²+(3-3)²) = √((-4)²+(0)²) = 4
After rotation
P'(3, 5)
Q'(3, 1)
we get the length
L' = √((3-3)²+(1-5)²) = √((0)²+(-4)²) = 4
we can say that L = L' = 4
P'Q' is equal in length to PQ.
I believe the answer is A, the standard deviation is preferable to the range as a measure of variation because the standard deviation takes into account all of the observations, whereas the range considers only the largest and the smallest. Range gives an overall spread of data from the lowest to the largest and thus can be influenced by anomalies, standard deviation on the other hand, takes into account the variable data/spread about the mean and allows for statistical use so inferences can be made.<span />
Answer:
see explanation
Step-by-step explanation:
Since K is at the midpoint of HN then HK = KN = 4x + 5, thus
HN = HK + KN ← substitute values
11x - 11 = 4x + 5 + 4x + 5, that is
11x - 11 = 8x + 10 ( subtract 8x from both sides )
3x - 11 = 10 ( add 11 to both sides )
3x = 21 ( divide both sides by 3 )
x = 7
Hence
KN = 4x + 5 = (4 × 7) + 5 = 28 + 5 = 33
Answer:
Step-by-step explanation:
a) Maternal gene = 0.25; Paternal gene = 0.25
Probability having a birth defect = 0.25 X 0.25 = 0.625
b) P(A) = 0.30; P(B) = 0.70
P(A)*P(B) = 0.30 X 0.70 = 0.021
For marriage:
25%: P(A)*P(A)*0.25 = 0.09 X 0.25 = 0.0225
65%: P(B)*P(B)*0.65 = 0.049 X 0.65 = 0.03185
10%: P(A)*0.10 = 0.03 and P(B)*0.10 = 0.07
P(A)*P(B) = 0.03 X 0.07 = 0.0021
Probability of a defect birth in the next generation = 0.0225 + 0.03185 + 0.0021 = 0.05645
c) 1. P(A)*P(A) = 0.09
2. P(B)*P(B) = 0.049
3. P(A)*P(B) = 0.021
