Who can help me with this entire page?

Mathematics

1 answer:

trasher [3.6K]2 years ago

8 0

Answer:

I'm not entirely sure what the question is but every thing under 12.5 is closer to 12, everything 12.5 and upwards like 12.87 would be closer to 13

You might be interested in

A slope of -2 and a y-intercept of -7

rosijanka [135]

Y=-2x-7
Y=mx+b where m is the slope and b is the y-intercept

8 0

3 years ago

Read 2 more answers

Select the best answer 7 x (-3) x (-2)^2=

vlada-n [284]

7(-3)(-2)²

-21(-2)²

-21(4)

= -84

I hope that's help !

6 0

4 years ago

What value of x makes the equation 5(7x-3)-x=-4x-(-9-2x) true? please help :)

stiv31 [10]

X = 2/3 makes the equation true.

Answer: x = 2/3

7 0

3 years ago

(5) Rewrite the integral Z 1 0 Z x 0 Z √ 1−x2 0 z dz dy dx in the order dy dx dz, and evaluate it. Hint: You will need a reasona

Natalija [7]

Looks like the integral is supposed to read

$\displaystyle\int_0^1\int_0^x\int_0^{\sqrt{1-x^2}}z\,\mathrm dz\,\mathrm dy\,\mathrm dx$

The same integral in the required order is

$\displaystyle\int_0^1\int_0^{\sqrt{1-z^2}}\int_0^xz\,\mathrm dy\,\mathrm dx\,\mathrm dz$

5 0

3 years ago

A rescue helicopter flew from its home base for 35 kilometers on a course of 330 degrees to pick up an accident victim. It then

artcher [175]

I've drawn a triangle to represent the journey (see attached.

The angle from Home to Victim to Hospital is:

a = $90 - (360 - 330) = 90- 30 = 60^o$

Using the cos rule, we can solve for the length x:

$a^2 = b^2 +c^2 - 2bccosA
\\x^2 = 35^2+25^2-2(35)(25)cos60
\\x^2 = 1850 - 875
\\x^2 = 975
\\x = \sqrt{975}
\\x = 31.2249...$

Using the cos rule, we can solve for angle b:

$a^2 = b^2 +c^2 - 2bccosA
\\35^2 = 31.22...^2+25^2-2(31.22...)(25)cosb
\\1225 = 975 + 625 - 1561.249...cosb
\\-375 = -1561.249...cosb
\\b = cos^{-1}( \frac{-375}{-1561.249...}) 
\\b = 76.1...$

So the bearing the helicopter has to travel is:

270 - 76.1 = <u>193.9 degrees (1 dp)</u>

And the distance it travels is <u>31.2 km (1 dp)</u>

5 0

3 years ago