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trapecia [35]
3 years ago
11

RELATION OR FUNCTION?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

FUNCTIONNNNN

Step-by-step explanation:

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A sum of money is shared among Ben, Jack, and Sarah in the ratio 6 : 8 : 10.
alexdok [17]

Answer:

B:J:S

6:8:10

6+8+10= 24 parts all together

Sarah has $50 and equals 10 parts. So, each part is worth $5. (50/10=5)

Thus, Ben receives 6 parts, with each part being $5. So, Ben gets $30. (6x5=30)

8 0
2 years ago
Read 2 more answers
Simone has 20 bills. One fifth of the bills are hundreds, 1/4 of them are fifties, 1/10 of them are $20s. The rest of the bills
larisa [96]
If Simone has 20 bills, then:

1/5 of 20 = 4 [hundreds]
1/4 of 20 = 5 [fifites]
1/10 of 20 = 2 [$20s]

4 * 100 + 5 * 50 + 2 * 20 = 400 + 250 + 40 = 690 [out of $780]
4 + 5 + 2 = 11 [out of 20 bills]

So now we can easily find out she had 9 bills of tens - because 20 - 11 = 9 or because (780 - 690) ÷ 10 = 90 ÷ 10 = 9.
5 0
3 years ago
On a 40‐point test, Steve received an 80%. How many points did he receive on the test?
jarptica [38.1K]

Answer:

Steve got 32 points

Step-by-step explanation:

Take the total score and multiply by the percentage received

40 * 80%

Change to decimal form

40 * .80

32

Steve got 32 points

7 0
2 years ago
Solve each pair of simulation equation.Giving both solutions. Multiply both equations by suitable numbers before adding/subtract
pashok25 [27]

Answer:

Step-by-step explanation:

I haven't got time to do all these by I'll give you the method in each case.

You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.

A . Multiply  equation 2 by 2 and subtract (to eliminate x)

- don't forget to multiply EACH TERM by 2.

B. Multiply  equation 2 by -2 and add.

C.  Multiply  equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so  you then add to eliminate y.

D.  Multiply equation 1 by 13 and equation  and equation 2 by 2 to eliminate x then add.

6 0
2 years ago
What is the l and w of a rectangular field of 40 ft perimeter?
shusha [124]
The perimeter doesn't tell you the dimensions.

With a 40-ft perimeter, there an infinite number of possibilities
for the length and with.  The only thing we know for sure is that
the sum of (length + width) is 20-ft.

The field could be . . .

1'  by  40'
2'  by  20'
3'  by  13-1/3 '
4'  by  10'
5'  by  8'
6'  by  6-2/3 '
3 0
3 years ago
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