I believe the answer is 5. I multiplied 5 to -4 and that’s -20 and I’m guessing since slope-intercept form is y=Mx+b I’m thinking b=4 and the slope being 5 matches the output. -16=5(-4)+4
Answer:

Step-by-step explanation:
<u>Given function is:</u>

Put x = 4
So,
![f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=f%284%29%20%3D%204%5E4%5C%5C%5C%5Cf%284%29%20%3D%20256%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
South west
Shifting 4 units left (decreasing in x-axis by 4 units)
Shifting 5 units down (decreasing in y-axis by 5 units)
Apply to every vertices coordinates(x - 4, y - 5)
New coordinates
A(-2, -1)
B(-1, -4)
C(1,0)
Answer:
Step-by-step explanation:
m
=4(-6, 8)/9
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.