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Andrew [12]
3 years ago
6

Pythagorean Theorem Word

Mathematics
1 answer:
diamong [38]3 years ago
7 0

Answer:

40 miles

Step-by-step explanation:

In the attached diagram, Point A is the starting point and C is the end point. We want to determine the distance from A to C.

The path driven forms a right triangle in which AC is the hypotenuse.

We therefore use the<u> Pythagorean Theorem</u> to solve for the AC.

Pythagorean Theorem: Hypotenuse^2=Opposite^2+Adjacent^2

|AC|^2=32^2+24^2\\|AC|^2=1600\\|AC|=\sqrt{1600}\\ |AC|=40$ miles

The  straight  line distance from the starting point is 40 miles.

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I believe the answer is 5. I multiplied 5 to -4 and that’s -20 and I’m guessing since slope-intercept form is y=Mx+b I’m thinking b=4 and the slope being 5 matches the output. -16=5(-4)+4
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3 years ago
If f(x)=4^x, find f(4)
lina2011 [118]

Answer:

\huge\boxed{f(4) = 256}

Step-by-step explanation:

<u>Given function is:</u>

f(x) = 4^x

Put x = 4

So,

f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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2 years ago
The coordinates of a triangle's vertices are A(2, 4), B(3, 1), and C(5, 5). The triangle undergoes a translation 4 units to the
AlekseyPX
South west

Shifting 4 units left (decreasing in x-axis by 4 units)
Shifting 5 units down (decreasing in y-axis by 5 units)

Apply to every vertices coordinates(x - 4, y - 5)

New coordinates

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5 0
3 years ago
. The slope of the line is 4/9, and it contains the point (-6,8). Enter an equation in point-slope form
Serga [27]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Two cylindrical containers, C and D, with different capacities are shown below. What is the total volume of liquid held in these
Zielflug [23.3K]

Answer:

Option D. (x + 4)(x + 1)

Step-by-step explanation:

From the question given above, the following data were obtained:

C = (6x + 2) L

D = (3x² + 6x + 9) L

Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:

Volume in C = ½C

Volume in C = ½(6x + 2)

Volume in C = (3x + 1) L

Volume in D = ⅓D

Volume in D = ⅓(3x² + 6x + 9)

Volume in D = (x² + 2x + 3) L

Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:

Volume in C = (3x + 1) L

Volume in D = (x² + 2x + 3) L

Total volume =?

Total volume = Volume in C + Volume in D

Total volume = (3x + 1) + (x² + 2x + 3)

= 3x + 1 + x² + 2x + 3

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Factorise

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(x + 4)(x + 1)

Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.

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3 years ago
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