Answer: I think the answer is Infinity.
Step-by-step explanation:
Answer:
10% 0f 70 is 7
Step-by-step explanation:
70÷10=7
10%=7
Answer:
![[B]=2](https://tex.z-dn.net/?f=%5BB%5D%3D2)
Step-by-step explanation:
![B=\left[\begin{array}{ccc}3x-5&-3+2y\\11-3x&2y-5\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3x-5%26-3%2B2y%5C%5C11-3x%262y-5%5Cend%7Barray%7D%5Cright%5D)
With 
and 
![B=\left[\begin{array}{ccc}3(3)-5&-3+2(4)\\11-3(3)&2(4)-5\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%283%29-5%26-3%2B2%284%29%5C%5C11-3%283%29%262%284%29-5%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{ccc}9-5&-3+8\\11-9&8-5\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9-5%26-3%2B8%5C%5C11-9%268-5%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%5C%5C2%263%5Cend%7Barray%7D%5Cright%5D)
solving the determinant of matrix B
![[B]=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]=(4.3-5.2)=(12-10)=2](https://tex.z-dn.net/?f=%5BB%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%5C%5C2%263%5Cend%7Barray%7D%5Cright%5D%3D%284.3-5.2%29%3D%2812-10%29%3D2)
Answer:
60%
Step-by-step explanation:
Write 0.6 as 0.60, which is 60 hundredths. 60 hundredths is 60 percent. You can also move the decimal point two places to the right to find the percent equivalent.
Answer:
A = (1/2)Cr . . . or . . . A = C^2/(4π)
Step-by-step explanation:
The diagram shows the area of the circle being redrawn as a parallelogram with the length of it being half the circumference and the height of it being the radius of the circle.
The area of the parallelogram is the product of its length (C/2) and its height (r), so you can compute ...
A = (1/2)Cr
___
Given only the circumference, C = 2πr, you can find the value of r by dividing by its coefficient:
C/(2π) = r
Using this in the above formula, the area can be found from the circumference only as ...
A = (1/2)C·(C/(2π))
A = C^2/(4π)
