1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
atroni [7]
3 years ago
6

Please answer :) ( Will give brainlst)

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Step-by-step explanation:

6. 7. 13

18. 10. 28

24. 17. 41

You might be interested in
Sandra has ribbons that are 2/6 meter 3/4meter and 4/9 meter long .She needs to use the ribbon longer than 2/3meter to make a bo
timurjin [86]

Answer:

3/4 meter

Step-by-step explanation:

Need Common denominators to compare size

2/6  3/4  4/9     which is longer than 2/3?

2/6 compared to 2/3.  2/6 = 2/6 and 2/3 = 4/6.  

2/6 < 2/3 so 2/6 is too short

3/4 compared to 2/3   3/4 = 9/12  and 2/3 =  8/12

3/4 > 2/3 so 3/4 is longer than 2/3

4/9 compared to 2/3  4/9 = 4/9 and 2/3 = 6/9

4/9 < 2/3 so 4/9 is too short

6 0
3 years ago
Read 2 more answers
How to write 14 ten thousands, 12 thousands
Neko [114]
Here's the sum of your problem..... 14 x 10,000 = 140,000 + 12,000 = 152,000 Hopefully this answers your question! :D
5 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED HELP ASAP.
Artyom0805 [142]
Your answer is 29.2 good sir.
Hope this helps :)
6 0
3 years ago
The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.
Kryger [21]

Hi There!

---------------------------------------------------------

Full Question:

The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.

Which can you tell about the mean temperatures for these two months?

There is not enough information to determine the mean temperatures.

The mean temperature for August is higher than June's mean temperature.

The mean temperature for June is equal to the mean temperature for August.

The high interquartile range for August pulls the mean temperature above June's mean temperature.

---------------------------------------------------------

Interquartile Range Formula: Q3 - Q1

Interquartile Range for August: 10

Interquartile Range for June: 8

---------------------------------------------------------

Median = Mean

June: 82

August: 82

---------------------------------------------------------

Answer: The mean temperature for June is equal to the mean temperature for August.

---------------------------------------------------------

Hope This Helps :)

5 0
3 years ago
What is the value of the product (3 – 2i)(3 + 2i)?<br> A. 5 <br> B. 9 + 4i<br> C. 9 – 4i <br> D. 13
UNO [17]

Answer:

D. 13

Step-by-step explanation:

You can do the product in the straight-forward way ...

... (3 -2i)(3 +2i) = 3·3 +3·2i -3i·3 -(2i)(2i)

... = 9 +6i -6i -4i² . . . . . note the middle two terms cancel

Recognize that i = √-1, so i² = -1. Then the sum is

... = 9 -4(-1) = 9+4 = 13

_____

Your graphing calculator can do this product, too.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Question 9 (3 points)
    8·2 answers
  • A tablet computer costs $189.69 including tax. It is marked up 30%.
    9·2 answers
  • On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 0.25). The line exits t
    7·2 answers
  • Two triangles have a scale factor of 5:7, If the area of the smaller triangle is 225cm squared what is the area of the larger tr
    8·1 answer
  • Can someone answer these two questions please
    15·1 answer
  • Numbers like -3, -2, -1, 0, 1, 2, 3 are called
    8·1 answer
  • May i get an answer? for 10 points
    8·2 answers
  • Solve: 14 + x = 18<br><br>a.) 32<br>b.) -4<br>c.) 4<br>d.) 16​
    7·2 answers
  • A cube with sides that are 2 cm has a mass of 48 g and its density would be <br> ___________ g/cm3.
    9·2 answers
  • Solve each equation for y (get into slope-intercept/y=mx + b form):
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!