X must be greater than 0 and y must be less than 0.
I hope this helped.
2. They are both straight lines. The solution of a linear system is where the two lines intersect, and if they're both straight lines, then they can only cross once.
See the picture attached.
Answer:
Difference of squares:
y^4−25
16x^2−81
Not difference of squares:
20m^2n^2−121
p^8−q^5
Step-by-step explanation:
y^4−25
(y²)² - 5²
16x^2−81
(4x)² - 9²
20m^2n^2−121
20 is not a perfect square
p^8−q^5
q⁵ is not a perfect square
You would have $60 after 5 years..I'm not 100% sure, sorry.