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Pachacha [2.7K]
2 years ago
7

Nico dropped the brand new bottle of dog shampoo and 3 ounces spilled out. He measures 1 and one-fourth ounces each time he sham

poos his dog and the bottle of shampoo originally contained 30 and one-half ounces. Which is the correct equation and value of x, the number of times Nico can bathe his dog using this one bottle?
1 and one-fourth x minus 3 = 30 and one-half; x = 22 times
1 and one-fourth x + 3 = 30 and one-half; x = 27 times
1 and one-fourth x + 3 = 30 and one-half; x = 22 times
1 and one-fourth x minus 3 = 30 and one-half; x = 27 times
Mathematics
2 answers:
MatroZZZ [7]2 years ago
8 0

Answer:

B

Step-by-step explanation:

Rama09 [41]2 years ago
7 0

Answer:

The answer is A (1 1/4x -3 = 30 1/2; x = 22 times), i just finished the test on edge 2021, good luck! :)

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Which compound most likely contains polar covalent bonds?<br> NaCl<br> AlF3<br> Br2<br> NF3
belka [17]

Answer: The correct answer is NF_3

Explanation:

In NF_3 molecule, there are three bond pairs and one lone pair present in the molecule. In a molecule, lone pair present on the nitrogen atom will have a dipole moment in upward direction where as total dipole moment formed by three fluorine atoms will be more in magnitude and it will be directed in downward direction which means that the net dipole moment will be in downward direction. As shown in image attached.

Hence, covalent bond present between nitrogen and fluorine will become polar in nature.

So, the correct answer is NF_3.

7 0
3 years ago
Read 2 more answers
Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible
Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

pq =    \sqrt{( {x2 - x1)}^{2}  + ( {y2 - y1)}^{2} }

or \:  \sqrt{( {5  + 3)}^{2} + ( {2 - 2)}^{2}  }

By simplifying it we get,

8

Now,

again finding the distance between PR,

pr = \sqrt{( {x2 - x1}^{2}  + ( {y2 - y1)}^{2} }

or,

\sqrt{( {x + 3)}^{2}  + ( {y - 2)}^{2} }

By simplifying it we get,

=  \sqrt{ {x}^{2} +  {y}^{2} + 6x  -  4y + 13  }

now, finding the distance of QR,

qr =  \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2}  }

or, by simplification we get,

\sqrt{ {x}^{2} +  {y}^{2}  - 10x - 4y + 29 }

now, equating PR and QR,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x  -  4y  + 13}  =  \sqrt{ {x}^{2}  +  {y}^{2} - 10x - 4y + 29 }

we cancelled the root ,

{x}^{2} +  {y}^{2} + 6x - 4y + 13 =  {x}^{2}   +  {y}^{2}   -10x - 4y + 29

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x - 4y + 13 }  =  8}

cancel the roots,

{x}^{2} +  {y}^{2}   + 6x - 4y + 13  = 8

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
The length of a planet's orbit around a star is approximately 17,650,000 km.
daser333 [38]

Answer:

1150 km/hr

Step-by-step explanation:

Formula for Average Speed is given as = Distance in Kilometers/ Time in Hours

In the question we are given the following parameters.

The length of a planet's orbit around a star = Distance = 17,650,000 km.

Time taken to complete a full orbit = 640 Earth days

Step 1

We need to convert the time in days to hours

1 Earth day = 24 hours

640 Earth days =

We cross multiply

640 Earth days × 24 hours

= 15360 hours.

Step 2

Average Speed = Distance in Kilometers/ Time in Hours

Average Speed = 17,650,000 km. /15360 hours

Average Speed = 1149.0885417 km/hr

Approximately to 3 significant figures=

1150 km/hr

Therefore, the planets average speed in kmh-1 to 3sf is 1150 km/hr

8 0
3 years ago
Suppose you decide to put $12,500 in an account earning 9% interest compounded quarterly. How much interest would you earn after
Vesnalui [34]

Step-by-step explanation:

you add 9% to a number by multiplying that number by 1.09.

because adding 9% gives us in the end 109% of the original amount.

anyway, the formula for quarterly compounded interest is

Cq = P [ (1+r)^(4*n) – 1 ]

P is the starting principal amount

r is the interest rate per quarter (= interest rate / 4)

n would be the number of years (= 1 in our case).

so, the interest after 1 year is

12500((1 + 0.09/4)⁴ - 1) = 12500(1.0225⁴ - 1) =

= 12500 × 0.093083319 = $1,163.541485 ≈ $1,163.54

8 0
1 year ago
Use 45-45-90 &amp; 30-60-90 Special Right Triangles to Solve. find the missing sir length. Leave you answers as radicals in simp
horsena [70]

Answer:5) x=y=7×6^1/2,6)x=38,y=19×3^1/2

7)m=n=18,8)u= 2×5^1/2,v=3

Step-by-step explanation: use trigonometry laws

8 0
2 years ago
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