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3 years ago

Which equation would represent exponential decay?

Mathematics

1 answer:

Aliun [14]3 years ago

7 0

If it was less spaced it would be easier to read can you message me the problem with it less messy

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A cruise ship is traveling at a speed of 20 knots. A knot is aproxamatley equal to 1.151 miles per hour what is the approximate

algol13

20 knots * 1.151 = 23.02 miles per hour There are 1,760 yards in a mile and 3,600 seconds in an hour. So, we multiply 23.02 * (1,760 / 3,600) which equals

11.2542222222 yards / second

4 0

3 years ago

Please answer this in two minutes

Anettt [7]

<h3>Answer: 77/85</h3>

Explanation:

Triangles HIG and FED are similar triangles. We know this because we have two pairs of angles that are congruent (angle G = angle D; angle I = angle E). Use the AA (angle angle) similarity theorem.

Since angles G and D are congruent, computing sin(D) is equivalent to finding sin(G)

sin(angle) = opposite/hypotenuse

sin(G) = IH/HG

sin(G) = 77/85

sin(D) = 77/85

3 0

3 years ago

What is the variable of 1 + 4i = 5i + 10

andrew11 [14]

Answer:

i = -9

Step-by-step explanation:

4i-5i =10 -1

-i= 9

i=-9

6 0

3 years ago

Find each. a. za_2 for the 99% confidence interval b. za_2 for the 98% confidence interval c. za_2 for the 95% confidence interv

irga5000 [103]

Answer:

a) Z = 2.575.

b) Z = 2.327.

c) Z = 1.96.

d) Z = 1.645.

e) Z = 1.88.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Question b:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Question c:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Question d:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Question e:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.94}{2} = 0.03$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.03 = 0.97$ , so Z = 1.88.

8 0

3 years ago

6.- Find the area under the standard normal distribution: to the left of z=-1.55.

Kisachek [45]

Answer:

$P(z$

Step-by-step explanation:

For this case we want to find this probability:

$P(z$

Because they want the area to the left of the value. We need to remember that the normal standard distribution have a mean of 0 and a deviation of 1.

We can use the following excel code: =NORM.DIST(-1.55,0,1,TRUE)

And we got:

$P(z$

The other possibility is use the normal standard table and we got a similar result.

5 0

4 years ago