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Komok [63]
3 years ago
9

What is the coefficient of the fifth term in (a + b)^9 ?

Mathematics
2 answers:
Margaret [11]3 years ago
8 0

remember a coefficient is the number in front of the variable

the coefficient in the fifth term is 9 since 9 is a number.

AnnZ [28]3 years ago
3 0

I agree with the first answer and if you are not sure what a variable is:

Variable- letters in algebra (I think)

Have a good day:)

- A bunny

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Answer:

C- Divide both sides by 3.

Step-by-step explanation:

In order to isolate the variable, we will have to remove all non-1 coefficients from the variable. Since 3b can be written as 3(b), b is being multiplied by 3. So the only way to isolate the variable is to do inverse operations, which would be to divide both sides of the inequality by 3.

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3 years ago
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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

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Step-by-step explanation:

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