If it's three or more, the probability is 100%.
However, I will assume that you intend to draw only two balls and that you don't replace the first ball in the bag for the second draw.
So you draw one ball. The probability that it's red is 8/14 = 4/7.
You draw again. The probability of getting a second red is 7 (red balls remains) / 13 (balls remaining).
Assuming that the results of the first and second draws are independent,the probability of drawing two red balls is therefore (4/7)*(7/13) = 4/13.
Now, suppose instead of a red on the first draw you got white. The probability of this is 6/14 = 3/7.
Given the first ball is white, the probability of drawing a second white is 5/13.
So the probability of drawing two whites is (3/7)*(5/13) = 15/91.
The outcomes of drawing two reds or two whites are independent of each other, so you can add the probabilities to get the probability of drawing two balls of the same colour, i.e.
4/13 + 15/91 = 43/91
If you prefer to express it as a percentage, it's approximately 47.25%.
Manny is a incorrect his logic doesn't not provide any specific evidence to support his theory
A tangent line connected to a line to the center of a circle creates a right angle
. The triangle formed is a right triangle so you can use the Pythagorean theorem to solve for the missing side.
WO = sqrt( 17^2 - 15^)
WO = 8
So if Bill runs 10 miles in those 4 days then we need to find out Val's.
2 and 3/5. Well, we already know 2*4=8
so 0.6 (which is 3/5) multiplied by 4 is 2.4.
8+2.4=10.4
So here are the results for the distance covered in 4 days :
Val = 10.4 miles
Bill = 10 miles
Therefore, I think Val covers the most distance in 4 days.
Hope I helped :)
25% + 40% +?% = 100%
65% + ?% = 100%
?% = 35%
.35*160 = 56
There are 56 grape fruit chews in the display case.
