Answer:
39 touchdowns and 13 fieldgoals
Step-by-step explanation:
Let t= touchdowns
f = fieldgoals
They scored 35 times
t+f = 35
Touchdown is 7 pts and fieldgoal is 3 pt
7t+3f = 193
Multiply the first equation by-7
-7t -7f =-245
Add this to the second equation
-7t -7f =-245
7t+3f = 193
----------------------
-4f =-52
Divide by -4
-4f/-4 = -52/-4
f = 13
Now we can find t
t+f = 35
t+13 = 52
Subtract 13 from each side
t+13-13 =52-13
t =39
<span>8r-rs when r=6 and s=5
</span><span>8(6) - (6)(5)
= 48 - 30
= 18
</span>
Answer:
B
Step-by-step explanation:
since the variable never become denominator, the highest power is 2, and the coefficient of x² is non zero
Answer:
I think it could be D
Step-by-step explanation:
Because if you move point K up a little they will be congruent , I’m not 100% sure tho
Answer:
9x4+126x3+648x2+1440x+1152
Step by step:
27(x^2+8x+16) / 3 (x^2+6x+8)
(27(x^2+8x+16) / 3) (x^2+6x+8)
(27(x^2+8x+16) / 3) (x^2) +(27(x2+8x+16) / 3) (6x)+(27(x2+8x+16)/3) (8)
9x4+72x^3+144x^2+54x^3+432x^2+864x+72x^2+576x+1152
9x4+126x3+648x2+1440x+1152