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Makovka662 [10]
3 years ago
15

3) Sumalee's school is selling tickets to the annual dance competition. On the first day of ticket sales the school

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

$380

Step-by-step explanation:

add the money then add the other numbers

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olga2289 [7]

-4(8+y)=90\implies8+y=-22.5\implies y=-30.5.

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Seventy-five percent of what number is 37.5?
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Step-by-step explanation:

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4 years ago
A line passes through the points (-5, 2) and (10.-1). Which is the equation of the line?
Igoryamba

Answer:

y= -1/5x + 1

Step-by-step explanation:

When looking for a line between two points, you want to use the following formula: (y2-y1)/(x2-x1) which finds your distance between points for the y and x coordinate to solve for your slope. y1 is the y coordinate from the first given point and x1 is the x coordinate from the first given point as well. this would go the same for x2 and y2 for the second given equation.

Next, we plug in our values so that we get (-1-2)/(10-(-5)). This will then lead us with -3/15 which simplifies to -1/5. This is our slope. Now that we have our slope we can rule out every option except the first for the answer. However, if we want to look for the entire answer we need to plug in one of our given values in the formula we have: y=-1/5x.

So to find the y-intercept, we can plug in any of the given coordinates so we can fo (10,-1) so that -1=-1/5(10)+b (b what added because we are putting the equation in slope-intercept, therefore we need to find the value b.) So we are left with -1=-2+b now we want to isolate b by adding 2 on both sides to cancel -2 and get 1=b. This would leave us with the equation y=-1/5x+1.

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Stolb23 [73]

Step-by-step explanation:

<em>( - 3 {x}^{2} - 9x) \div (x + 3)</em>

<em>This </em><em>is </em><em>the</em><em> </em><em>original </em><em>equation</em><em> </em><em>so</em><em> </em><em>you </em><em>will</em><em> </em><em>open</em><em> </em><em>the</em><em> </em><em>brackets</em><em>.</em>

<em>- 3 {x}^{2}  - 9x \div x + 3</em>

<em>The</em><em> </em><em>x</em><em> </em><em>will</em><em> </em><em>cross</em><em> </em><em>the</em><em> </em><em>division </em><em>sign</em><em> </em><em>making</em><em> </em><em>it</em><em> </em><em>times</em><em> </em><em>x</em><em>.</em>

<em>3 {x}^{2}  - 9x \times x = 3</em>

<em>So</em><em> </em><em>you </em><em>will</em><em> </em><em>proceed</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>9</em><em>x</em><em> </em><em>by</em><em> </em><em>x</em><em> </em><em>making </em><em>it</em><em>;</em>

<em>3 {x}^{2}  - 9 {x}^{2} = 3</em>

<em>So</em><em> </em><em>you</em><em> </em><em>will</em><em> </em><em>subtract</em><em> </em><em>9</em><em>x</em><em>²</em><em> </em><em>from</em><em> </em><em>3</em><em>x</em><em>²</em><em> </em><em>which</em><em> </em><em>won't </em><em>be</em><em> </em><em>possible </em><em>so</em><em> </em><em>it </em><em>will</em><em> </em><em>be</em><em> </em><em>negative</em><em>.</em>

<em>- 6 {x}^{2} = 3</em>

<em>Then</em><em> </em><em>you </em><em>will</em><em> </em><em>square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>making</em><em> </em><em>it</em><em>;</em>

<em>- \sqrt{6 {x}^{2} } =  \sqrt{3}</em>

<em>So</em><em> </em><em>the</em><em> </em><em>²</em><em> </em><em>will</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>√</em><em> </em><em>leaving </em>

<em>-6x</em><em>=</em><em>√</em><em>3</em>

<em>-6x</em><em>=</em><em>1</em><em>.</em><em>7</em><em>3</em><em>(</em><em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em>6</em><em>)</em>

<em>x</em><em>=</em><em>0</em><em>.</em><em>2</em><em>8</em><em>8</em>

<em>That</em><em>'s</em><em> </em><em>the</em><em> </em><em>final </em><em>answer</em><em>.</em>

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