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3 years ago

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What is exponential growth and exponential decay?

2 answers:

Naya [18.7K]3 years ago

8 0

Answer:

In exponential growth, the rate of growth is proportional to the quantity present. In other words, y′=ky. Systems that exhibit exponential growth have a constant doubling time, which is given by (ln2)/k. Systems that exhibit exponential decay have a constant half-life, which is given by (ln2)/k

Step-by-step explanation:

There is your answer good luck! - Alexsys

vfiekz [6]3 years ago

7 0

Answer:

In some cases with exponential functions, as the value of x increases, the value of y also increases. This is a direct relationship known as exponential growth. As the value of x increases, the value of y grows rapidly. ... This is an inverse relationship known as decay.

Step-by-step explanation:

I hope this answer has helped you

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Which equation in slope intercept represents the line that goes through the points (-1, 6) and (1, -2)

Afina-wow [57]

Answer:

D) y=-4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

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m=-8/2

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y-6=-4(x-(-1))

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3 years ago

g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

vredina [299]

Answer:

$-\frac{10}{3}ft/s$

Step-by-step explanation:

We are given that

Height of man=5 foot

$\frac{dy}{dt}=-10ft/s$

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

$\frac{20}{5}=\frac{x+y}{x}$

$4=\frac{x+y}{x}$

$4x=x+y$

$4x-x=y$

$3x=y$

$3\frac{dx}{dt}=\frac{dy}{dt}$

$\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s$

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light= $-\frac{10}{3}ft/s$

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