Common factors of 60 and 126 are:
1, 2, 3, 6
Hope this helps
First of all we will understand the question!!
<em>The</em><em> </em><em>question</em><em> </em><em>is</em><em> </em><em>saying</em><em> </em><em>that</em><em> </em><em>you</em><em> </em><em>are</em><em> </em><em>given</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>give</em><em> </em><em>the</em><em> </em><em>maximum</em><em> </em><em>profit</em><em>.</em><em>.</em><em>.</em><em> </em><em>Lets</em><em> </em><em>solve</em><em> </em><em>it</em><em> </em><em>by</em><em> </em><em>finding</em><em> </em><em>the</em><em> </em><em>extrema</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>vertex</em>
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- <u>Identify the coefficients a and b of the quadratic function</u>
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- <u>Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a</u>
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- <u>Solve</u><u> </u><u>the</u><u> </u><u>equation</u><u> </u><u>for</u><u> </u><u>x</u><u> </u>
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- <u>The maximum of the quadratic function is at </u><u>x</u><u>=</u><u>3</u>
We now look at a right-angled triangle with sides a, b and c, as shown opposite. Pythagoras' Theorem states that, for any right-angled triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the two shorter sides.
-(x+2)^2(x-4)^2
Not that if x= -2 and x=4 they will look like this in an equation: (x+2) and (x-4)
When (x+2) and (x-4) are set equal to zero and you solve for x, x will equal x= -2 and x=4
If they have double roots, they have a multiplicity of 2 (per root) meaning they will bounce off of the x-axis. Multiplicity can be found by using exponents.
The negative in front flips the function over the x-axis and holds true to the given limit.