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Savatey [412]
2 years ago
13

How do i figure out the answer

Mathematics
2 answers:
natali 33 [55]2 years ago
5 0

Answer:

a2-14=-5a is a=2, a=-7

Step-by-step explanation:

Add 5a to both sides ax^{2}-14+5a= -5a+5a

Simplify ax^{2}+5a-14=0

after we solve with the quadratic formula we get -7

Troyanec [42]2 years ago
4 0

Answer:

<h2>Refer to the attachment and Thank you for asking:)</h2>

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The inequality 7-2/3 &lt; x-8 is equivalent to
inn [45]

X>43/3

Or X>29/3

Depending if you mean (7-2)/3 or 7-(2/3)

5 0
3 years ago
Daniel spent 3 hours babysitting for his brother. He and the children played games for 1 3/4 hours and watched television for 1/
____ [38]

Answer:

He spent 3/4 of an hour reading stories

Step-by-step explanation:

Sorry I dont have time :(

8 0
2 years ago
D=<img src="https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bx%7D%20%281-%28-5%29x%5E%7B2%7D%20%2B%20%28-5-3%29x%5E%7B2%7D" id="TexFormula1
aleksandr82 [10.1K]
Bro i don’t know either
3 0
3 years ago
{[20/(8+2)]^6+6}/(4^2/2)
Naddika [18.5K]
So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)
7 0
3 years ago
Read 2 more answers
Can anyone help me with this?
Iteru [2.4K]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>

3 0
2 years ago
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