All categories

3 years ago

Match the term and the definition

Physics

1 answer:

sineoko [7]3 years ago

3 0

Answer:

1. When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called stationary front.

2. If warm or more humid air presses forward and colder or drier air draws back, the boundary is called warm front.

3. If colder or drier air presses forward and warmer or more humid air draws back, the boundary is called cold front.

4. Sometimes a warm air mass can get caught between two cold fronts, which can force the warm air up into a wedge shape is called occluded front.

You might be interested in

Which of these formulas represents 1 atom of sodium (Na) chemically combined with another element?

Andru [333]

The answer is B. because NaCl are just two elements with one atom from each element

3 0

3 years ago

Read 2 more answers

Mass of mercury = 57 g Volume of mercury = 4.2 mL

kari74 [83]

24 beautiful women and women who have a good relationship and you can get a good laugh and

7 0

3 years ago

An airplane is flying over the South Pole. Which arrow correctly shows the direction gravity pulls the plane? (2 points)

tatyana61 [14]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

A force in the x direction acts on a particle moving also in the x direction, producing a potential energy U(x)=Ax4 where A=0.63

poizon [28]

Answer:

The magnitude of the force is 1.29*10^-3N in the positive x direction

Explanation:

In order to calculate the magnitude and direction of the force, you take into account that the force is the space derivative of the potential enrgy, as follow:

$F(x)=-\frac{dU(x)}{dx}$ (1)

where:

$U(x)=Ax^4\\\\A=0.0630\frac{J}{m^4}$

You replace the expression for U into the equation (1) and solve for F:

$F(x)=-\frac{d}{dx}[Ax^4]=-4Ax^3$ (2)

The force on the particle, for x = -0.080m is:

$F=-4(0.630\frac{J}{m^4})(-0.0800m)^3=1.29*10^{-3}N$

The magnitude of the force is 1.29*10^-3N in the positive x direction

7 0

3 years ago

A soccer ball of mass 0.4 kg is moving horizontally with a speed of 20 m/s when it is kicked by a player. The kicking force is s

frutty [35]

Answer:

Explanation:

The ball was moving with velocity of 20 m /s earlier in horizontal direction . Due to kicking, additional V velocity was added to it at 40° because he kicked it at this angle but the ball travelled in the direction of resultant which was making an angle of 30° with the horizontal .

From the relation of inclination of resultant

Tan θ = V sinα / (u + V cosα) where α is angle between u and V , θ is inclination of resultant

Tan30 = $\frac{Vsin40}{20+ Vcos40}$

$\frac{1}{\sqrt{3 } } =\frac{V\times .64}{20+ V\times.766}$

20 + .766 V = 1.11 V

20 = .344 V

V = 58 m /s

To know the force , we shall apply concept of impulse

F x t = mv , F is force for time t creating a change of momentum mv

F x .1 = .4 x 58

F = 232 N

6 0

3 years ago