Answer:
(a) K₁ = 2.205 J.
(b) K₂ = 5.733 J.
(c) K₂/K₁ = 2.6.
Explanation:
Kinetic Energy: This can be defined as the energy of a body in motion. The Unit of kinetic energy is J.
Mathematically kinetic energy can be represented as,
K = 1/2mv²
(a)
K₁ = 1/2m₁v₁²............................ Equation 1
Where K₁ = kinetic energy of the smaller bullet, m₁ = mass of the smaller bullet, v₁ = velocity of the smaller bullet.
<em>Given: m₁ = 2.5 g = 2.5/1000 = 0.0025 kg, v = 42 m/s.</em>
<em>Substituting these values into equation 1</em>
K₁ = 1/2(0.0025)(42)²
K₁ = 4.41/2
K₁ = 2.205 J.
(b)
K₂ = 1/2m₂v₂²............................. Equation 2
Where K₂ = kinetic energy of the heavier bullet, m₂ = mass of the heavier bullet, v₂ = velocity of the heavier bullet.
Given: m₂ = 6.5 g = 6.5/1000 = 0.0065 kg, v₂ = 42.0 m/s
Substituting into equation 2,
K₂ = 1/2(0.0065)(42)²
K₂ = 11.466/2
K₂ = 5.733 J.
(c)
The ratio: K₂/K₁ = 5.733/2.205
K₂/K₁ = 2.6.
Answer:
The time rate of change of flux is
Explanation:
Given :
Current A
Area of plate
Plate separation m
(A)
First find the capacitance of capacitor,
Where
F
But
Where
Now differentiate above equation wrt. time,
Therefore, the time rate of change of flux is
The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3.
density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3.
the answer is 1 g/cm^3. I hope this helps!
Answer:
a) Deceleration = 201.76 m/s^2
b) Distance traveled = 197.68 m
Explanation:
Initial Speed = 632 mi/h
Initial Speed (in meters/second) = (632 * 1.609 * 1000) / (60 * 60) = 282.4 m/s
Time to decelerate = 1.4 seconds
a) Change in speed = Acceleration * time
-282.4 = Acceleration * 1.4
Acceleration = -201.76 m/s^2
Deceleration = 201.76 m/s^2
b) Distance traveled = average speed * time
average speed = 282.4 / 2 = 141.2 m/s
Distance traveled = 141.2 * 1.4
Distance traveled = 197.68 m
<span>So this question based on doppler effect
Here apparent freq = freq of sound *(speed of sound-speed of observer)/(speed of sound-speed of source)
given
freq of sound=2000
speed of observer= 20
speed of source= 30
taking speed of sound as 343 m/s
apparent freq = 2000 [343 - 20] / [343 - 30] = 2063.90 Hz</span>