Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
The missing coordinates of the parallelogram is (m + h, n).
Solution:
Diagonals of the parallelogram bisect each other.
Solve using mid-point formula:
Here 
<u>To find the missing coordinate:</u>
Let the missing coordinates by x and y.
Here 
Now equate the x-coordinate.
Multiply by 2 on both sides of the equation, we get
m + h = x
x = m + h
Now equate the y-coordinate.
Multiply by 2 on both sides of the equation, we get
n = y
y = n
Hence the missing coordinates of the parallelogram is (m + h, n).
If we want to select a ball of each colour we have to extract 175+150+75+70+1=471 balls
P=471/500 is the answer
Your answer would be 63.33. ((: ❤️
Answer:
41/45
Step by Step Explanation:
Add: 8/
10
+ 1/
9
= 8 · 9/
10 · 9
+ 1 · 10/
9 · 10
= 72/
90
+ 10/
90
= 72 + 10/
90
= 82/
90
= 2 · 41/
2 · 45
= 41/
45
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/
45
.
In other words - eight tenths plus one ninth = forty-one forty-fifths.
