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-Dominant- [34]
2 years ago
5

You and a partner tend 3 machines that run continuously. One prints 200 plastic bottles per hour, one prints 180 plastic bottles

per hour, and one prints 150 plastic bottles per hour. If the machines work at their average rates, how many plastic bottles will they print during the 8.5 hours you are at the factory for your shift?
Mathematics
2 answers:
strojnjashka [21]2 years ago
6 0
The first machine does 200 in 1 hour, so in 8.5 hours it will then do 200 * 8.5.

the second machine does 180 in 1 hour, so in 8.5 hours it will then do 180 * 8.5.

the third machine does 150 in 1 hour, so in 8.5 hours it will do then 150 * 8.5.

how many bottles will they all do in total on that time?

(200 * 8.5) + (180 * 8.5) + (150 * 8.5)
MAXImum [283]2 years ago
4 0

Answer:

4,505

Step-by-step explanation:

(200 * 8.5) + (180 * 8.5) + (150 * 8.5)

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For this case we must simplify the following expression:

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To do this, we convert the mixed numbers to improper fractions:

\frac {4 * 3 + 3} {4} - \frac {14 * 1 + 3} {14} =\\\frac {15} {4} - \frac {17} {14} =\\\frac {14 * 15-4 * 17} {4 * 14} =\\\frac {210-68} {56} =\\\frac {142} {56} =\\\frac {71} {28} =\\2 \frac {15} {28}

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\frac {71} {28} = 2 \frac {15} {28}

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How many gallons of a 20% acid solution should be mixed with 30 gallons of a 40% solution, to obtain a mixture of 30% acid solut
Alexeev081 [22]

Answer:

30 gallons of 20% acid solution should be mixed.

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Let x gallons of a 20% acid solution was mixed with 30 gallons of a 40% solution, to obtain a mixture of 30% acid solution.

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Now concept to solve this question is

20%.(x) + 40%.(30) = 30%.(x + 30)

0.20(x) + 0.40(30) = 0.30(x + 30)

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