All categories

3 years ago

Hellllllllpppppppppppp!!

Mathematics

1 answer:

alekssr [168]3 years ago

4 0

Answer:

120 and can I have brainliest

Step-by-step explanation:

You might be interested in

What is the surface area

klasskru [66]

If you notice the picture below

the hexagonal pyramid, is really just a hexagon at the bottom, 6 sides,
and 6 triangles stacked up to each other at the edges

so.. just get the area of the hexagon and the triangles, and add them up, that'd be the surface area of the pyramid

a triangle's area, you'd know is just 1/2 bh, and you have both of those there

now, for the hexagon, notice, we're given the length from the center to one of the sides, namely the "apothem"

thus $\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{2}\cdot an\cdot s\qquad 
\begin{cases}
a=apothem\\
n=\textit{number of sides}\\
s=\textit{length of one side}\\
----------\\
n=6\\
s=22\\
a=11\sqrt{3}
\end{cases}$

7 0

4 years ago

What is the slope of this line?

HACTEHA [7]

The slope of this line is -1 because it goes down one and to the right one

6 0

4 years ago

Read 2 more answers

Which equation could be used to find the total amount earned, T, for working h hours at d dollars per hour?

anastassius [24]

Well, for each $h$ hour you work, you are going to earn $d$ dollars.

Given that we are keeping a constant rate of adding $d$ given the number of hours $h$ , we can say that $T$ is the following:

$T = hd$

For example, working at 8 dollars per hour will get the following equation:

$T = 8h$

For every hour you work, you receive another 8. Thus, we are multiplying them together.

The final equation is T = hd.

8 0

3 years ago

(4) use the method of lagrange multipliers to determine the maximum value of f(x, y) = x a y b (the a and b are two fixed positi

wlad13 [49]

Assuming $f(x,y)=x^ay^b$ . We have Lagrangian

$L(x,y,\lambda)=x^ay^b+\lambda(x+y-1)$

with partial derivatives (set to 0)[/tex]

$L_x=ax^{a-1}y^b+\lambda=0\implies ax^{a-1}y^b=-\lambda$
$L_y=bx^ay^{b-1}+\lambda=0\implies bx^ay^{b-1}=-\lambda$
$L_\lambda=x+y-1=0$

$\implies ax^{a-1}y^b=bx^ay^{b-1}\implies -bx+ay=0$
$x+y-1=0\implies x+y=1$

Solving this system of linear equations yields $x=\dfrac a{a+b}$ and $y=\dfrac b{a+b}$ as the sole critical point, which in turn gives a maximum value of $f\left(\dfrac a{a+b},\dfrac b{a+b}\right)=\dfrac{a^ab^b}{(a+b)^{a+b}}$ .

8 0

3 years ago

Graduate Management Aptitude Test (GMAT) scores are widely used by graduate schools of business as an entrance requirement. Supp

AlekseyPX

Answer:

(262, 690)

Step-by-step explanation:

Given that :

Mean score = 476

Standard deviation, s = 107

2 standard deviations above and below the mean :

Mean ± 2s

Hence,

2 standard deviations below :

476 - 2(107)

476 - 214 = 262

2 standard deviations above

476 + 2(107)

476 + 214 = 690

5 0

3 years ago