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serious [3.7K]
3 years ago
9

Please solve this problem for me.

Mathematics
2 answers:
xenn [34]3 years ago
7 0

He might have done it backwards.

1/63

and could be 63 miles in 1 hour

63/1.

Because the graph looks good. (i think)

iragen [17]3 years ago
6 0

Answer:

It is 63 or 63/1. Billy used change in x over change in y, and the correct formula for slope is the change in y over the change in x.

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4 sheets
Explanation
30 divided by 9 gives you 3.333333
But you can’t have 3 1/3 of a sticker sheet so you round up to 4 sheets
5 0
3 years ago
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Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
Can you guys help? Hopefully the last question of the day/night!
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Answer and explain:

1st person: 70 % throws

70/100x80 = 56 out of 80 throws

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60/100x80 = 48 out of 80 throws

3rd person 50% throws

50/100x80 = 40 out of 80 throws

56+48+40/80x3 = 77/120​

One equation that gives the estimated number of free throws (all the 3 people) is 77 out of 120. The best player will make about 56 out of 80 free throws.

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