h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]
Answer:
1
Step-by-step explanation:
If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.
A function for the rate of change of G(t) is given by G'(t).
G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.
d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2
G'(t) = -2t + 2
This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.
So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1
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Geometric series are in the form of
Where a is the first term and r is the common ratio .
And it is given that
r=-3,2
So the first five terms are
= 2-6+18-54+162 or 2+4+8+16+32
= 122 or 62
Lol i did this on my calculator
this is what i got
4.58804211
idk if it will help
Answer: literal language
hope this helps :)
