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Pepsi [2]
3 years ago
11

Identify the error in this column: (x2 + 3x + 18) = (x + 3)(x + 6)

Mathematics
2 answers:
const2013 [10]3 years ago
8 0

x^2+3x+18 = (x+3)(x+6)

↝ The error here is that (x+3)(x+6) doesn't make 3x in the middle here.

↝ From (x+a)(x+b) = x²+bx+ax+ab = x²+(a+b)x+ab

Now we let a = 3 and b = 6

Let's check the answer.

Given a = 3 and b = 6 (From the polynomials given.)

(x+a)(x+b) = x²+(a+b)x+ab

(x+3)(x+6)=x²+(3+6)x+(3*6)

(x+3)(x+6)=x²+9x+18

As you can see that the error here is that (x+3)(x+6) doesn't make 3x in the middle of polynomial. Therefore the error here is only 3x as proven.

inessss [21]3 years ago
3 0

Answer:

I think the error is that the variable x came before the whole number 2.

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Answer:

C. Both Carter and Demi are correct and would get the same answer.

Step-by-step explanation:

Here, the given polynomial is : P(x) =6x^2 + 4x + 3

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Now, according to the given question:

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Now, Carter divide P(x) by Q (x) with LONG DIVISION METHOD.

If we divide P(x) by Q(x) by Long division, we get:

\frac{P(x)}{Q(x)}  = \frac{(6x^2 + 4x + 3)}{(2x)}  = 3x +  2 + \frac{3}{2} x = R(x)

Also, if Demi divides each term of P(x) by The given monomial (2x) , we get:

\frac{P(x)}{Q(x)}  = \frac{(6x^2 + 4x + 3)}{(2x)}  = \frac{6x^2}{2x}  + \frac{4x}{2x} +\frac{3}{2x} \\= 3x +  2 + \frac{3}{2}  = R(x)

⇒In both the case, R(X)Quotient is SAME.

Hence, Both Carter and Demi are correct and would get the same answer.

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