Answer and Step-by-step explanation:
The first answer: Congruent
The second answer: Reflective Property
Angle D reflects on itself, making it congruent to itself.
The third answer: Are
The sides and angle are congruent to the other sides and angle because of the Given statement and SAS.
#teamtrees #WAP (Water And Plant)
Answer:
1. -21
2. 0
3. ![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
Step-by-step explanation:
1. 18 = ![-\frac{6}{7} h](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B7%7D%20h)
multiply both sides by the reciprocal of -6/7.
18 = ![-\frac{6}{7} h](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B7%7D%20h)
![(-\frac{7}{6} )](https://tex.z-dn.net/?f=%28-%5Cfrac%7B7%7D%7B6%7D%20%29)
-21 = h
-------------------
2. ![-\frac{3}{4} x=\frac{21}{8} x](https://tex.z-dn.net/?f=-%5Cfrac%7B3%7D%7B4%7D%20x%3D%5Cfrac%7B21%7D%7B8%7D%20x)
find the LCM of both fractions.
LCM = 8
multiply both fractions by the LCM
![-\frac{3}{4} x(8)=\frac{21}{8} x(8)](https://tex.z-dn.net/?f=-%5Cfrac%7B3%7D%7B4%7D%20x%288%29%3D%5Cfrac%7B21%7D%7B8%7D%20x%288%29)
-6x = 21x
subtract 21x from both sides
-6x-21x = 21x-21x
-27x = 0
isolate x
-27x/-27 = 0
x = 0
-------------------
3. ![-\frac{1}{2} z=\frac{5}{12}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%20z%3D%5Cfrac%7B5%7D%7B12%7D)
multiply both sides by the reciprocal of -1/2.
![-\frac{1}{2} z(-2)=\frac{5}{12}(-2)](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%20z%28-2%29%3D%5Cfrac%7B5%7D%7B12%7D%28-2%29)
z = ![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
hope this helps :)
expression represents the area of Dylan’s room
<h3><u>
Solution:</u></h3>
Given that,
Length of room = ![x^2 -2x+8](https://tex.z-dn.net/?f=x%5E2%20-2x%2B8)
Width of room = ![2x^2 + 5x - 7](https://tex.z-dn.net/?f=2x%5E2%20%2B%205x%20-%207)
To find: Expression that the area (lw) of Dylan’s room
Since bedroom is generally of rectangular shape, we can use area of rectangle
<em><u>The area of rectangle is given as:</u></em>
![\text {area of rectangle }=\text { length } \times \text { width }](https://tex.z-dn.net/?f=%5Ctext%20%7Barea%20of%20rectangle%20%7D%3D%5Ctext%20%7B%20length%20%7D%20%5Ctimes%20%5Ctext%20%7B%20width%20%7D)
Substituting the given expressions of length and width,
![area = (x^2 -2x+8)(2x^2 + 5x - 7)](https://tex.z-dn.net/?f=area%20%3D%20%28x%5E2%20-2x%2B8%29%282x%5E2%20%2B%205x%20-%207%29)
We multiply each term inside first parenthesis with each term inside the second parenthesis.
So it becomes,
![2x^4 + 5x^3 - 7x^2 -4x^3 -10x^2 +14x +16x^2 +40x - 56](https://tex.z-dn.net/?f=2x%5E4%20%2B%205x%5E3%20-%207x%5E2%20-4x%5E3%20-10x%5E2%20%2B14x%20%2B16x%5E2%20%2B40x%20-%2056)
Now combine like terms,
![2x^4 + x^3 - x^2 +54x - 56](https://tex.z-dn.net/?f=2x%5E4%20%2B%20x%5E3%20-%20x%5E2%20%2B54x%20-%2056)
Thus the above expression represents the area of Dylan’s room
Tbh with you i really don’t know